Find the domain of the graphed function
1 answer:
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In "slope-intercept form"
y = mx +b
the value "m" is called the slope, and the value "b" is called the intercept.
There is another form for the equation of a line, called "point-slope form".
y = m(x -h) +k
where m is still the slope and (h, k) correspond to the (x, y) of the point.
If you write the equation of your line in this "point-slope form", it is easily manipulated to be in the "slope-intercept form".
Fill in
m = (-3/5)
h = -4
k = 0
y = (-3/5)(x -(-4)) +0
Now, you simplify this by using the distributive property.
y = (-3/5)x -(3/5)*4
y = (-3/5)x -12/5 . . . . . . . . . the desired equation
_____
Your understanding of math improves immensely when you become familiar with the terminology. A lot of the rest of it is pattern matching--identifying the parts of one expression that correspond to the parts of another one.
(You will see another version of the "point-slope form", but I find this one the easiest to use for manipulating the equation to other forms.)
y = mx +b
the value "m" is called the slope, and the value "b" is called the intercept.
There is another form for the equation of a line, called "point-slope form".
y = m(x -h) +k
where m is still the slope and (h, k) correspond to the (x, y) of the point.
If you write the equation of your line in this "point-slope form", it is easily manipulated to be in the "slope-intercept form".
Fill in
m = (-3/5)
h = -4
k = 0
y = (-3/5)(x -(-4)) +0
Now, you simplify this by using the distributive property.
y = (-3/5)x -(3/5)*4
y = (-3/5)x -12/5 . . . . . . . . . the desired equation
_____
Your understanding of math improves immensely when you become familiar with the terminology. A lot of the rest of it is pattern matching--identifying the parts of one expression that correspond to the parts of another one.
(You will see another version of the "point-slope form", but I find this one the easiest to use for manipulating the equation to other forms.)
Answer:
Step-by-step explanation:
Alright, lets get started.
Please refer the diagram I have attached.
The width of the room is 30 meters.
If two beams will be making an angle, they will half the width.
There will be a right triangle made, so using SOH CAH TOA,
taking cos inverse
x =
x = 28.07° : Answer
Hope it will help :)
