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Ira Lisetskai [31]
3 years ago
9

In a sample of 150 cars, 18 cars failed a safety inspection. The sampling method had a margin of error of 0.02

Mathematics
1 answer:
mestny [16]3 years ago
7 0

Answer:  

(Lower limit, Upper limit) = (0.10, 0.14)

(Lower limit, Upper limit) = (10%, 14%)

Step-by-step explanation:  

Total number of cars = 150

Cars that failed the safety inspection = 18

The proportion is given by

p = 18/150

p = 0.12

p = 12%

The confidence interval is given by

p ± margin of error

Where margin of error is 0.02

0.12 ± 0.02

Lower limit = 0.12 - 0.02

Lower limit = 0.10

Lower limit = 10%

Upper limit = 0.12 + 0.02

Upper limit = 0.14

Upper limit = 14%

(Lower limit, Upper limit) = (0.10, 0.14)

(Lower limit, Upper limit) = (10%, 14%)

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Vlad1618 [11]
P = 2(L + W)
P = 96
L = 2W + 8

96 = 2(2W + 8 + W)
96 = 2(3W + 8)
96 = 6W + 16
96 - 16 = 6W
80 = 6W
80/6 = W
40/3....or 13 1/3 ft <== width

L = 2W + 8
L = 2(40/3) + 8
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3 years ago
Decimal a = 2.5m; decimal b = 4.0m; decimal c = 12.7m; int i = 4; int j = 8; int k = 17; What is the value of x after the follow
ra1l [238]

Answer:

Option b(0.5) is the correct answer for the above question.

Step-by-step explanation:

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  • Then there are the other three statemen which is used to declare the three variable of type integer which names are i,j and k and initialize them to a value 4,8 and 17.
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Shalnov [3]
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3 years ago
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Part B:

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