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aev [14]
3 years ago
7

Maddie babysat for 3 hours and earned $22.50.

Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

jurnls babysitting cost more

Step-by-step explanation:

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Tuerying ue correct expression
AleksAgata [21]
Hi how are you today hopefully your well
8 0
3 years ago
According to Nielsen Media Research. of all the U.S. households that owned at least one television set, 83% had two or more sets
Rudik [331]

Answer:

The proportion of U.S. households that owned two or more televisions is 83%.

Step-by-step explanation:

To determine whether the proportions of U.S. households that owned two or more televisions is less than 83% or not let us perform a hypothesis test for single proportion.

<u>Assumptions:</u>

The sample size (<em>n</em>) selected by the local cable company is 300 which is quite large. Then according to the Central limit theorem the sampling distribution of sample proportion follows a normal distribution with mean <em>p</em> and standard deviation \sqrt{\frac{p(1-p)}{n} } .

Since the sampling distribution of sample proportions follows a normal distribution use the <em>z</em>-test for one proportion to perform the test.

<u>The hypothesis is:</u>

H_{0} : The proportion of U.S. households that owned two or more televisions is 83%, i.e. p=0.83

H_{1} :The proportion of U.S. households that owned two or more televisions is less than 83%, i.e. p< 0.83

<u>Decision Rule:</u>

At the level of significance α = 0.05 the critical region for a one-tailed <em>z</em>-test is:

\\ Z\leq -1.645\\

**Use the <em>z</em> table for the critical values.

So, if \\ Z\leq -1.645\\ the null hypothesis will be rejected.

<u>Test statistic value:</u>

z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

Here \hat{p} is the sample proportion.

Compute the value of \hat{p} as follows:

\hat{p}=\frac{X}{n} \\=\frac{240}{300}\\ =0.80

Now compute the value of the test statistic as follows:

z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}\\=\frac{0.80-0.83}{\sqrt{\frac{0.83*(1-0.83)}{300} } } \\=-1.383

The test statistic is -1.383 which is more than -1.645.

Thus, the test statistic lies in the acceptance region.

Hence we fail to reject the null hypothesis.

<u>Conclusion:</u>

At 0.05 level of significance we fail to reject the null hypothesis stating that the proportion of U.S. households that owned two or more televisions is  83%.

6 0
3 years ago
Kanya is comparing the rate for shipping and handling for two online shopping websites. For the item she has selected, Big Barga
kari74 [83]
Answer:

D. Discount Deals Depot; $15.20

Why?
Lets do Big Bargain Bonanza first.
$8.00 would stay the same as it is for handling. The only number that would change is $1.25, it uses the the words PER pound for shipping.

Your equation would look like this with p being how many pounds Kanya is shipping:
$8.00+$1.25p

Now we just plug in the numbers.
$8.00+$1.25(6)=
$8.00+$7.50=
$15.50

The same games for Discount Deals Depot.
$9.50+$0.95(6)=
$9.50+$5.70=
$15.20

So in conclusion Discount Deals Depot; $15.20 is cheaper than Big Bargain Bonanza;$15.50
6 0
2 years ago
Find the product of two numbers whose sum is 11 and difference is 3.
Nuetrik [128]
Answer: I think it’s A - 28

Step by step:

For the sum : if you add 11 + 17 it gives you 28.

For the division: if you divided 28 by 3 it would equal 9.3.

So I think it’s 28 I’m not so sure
5 0
3 years ago
Pleaseeee 10 points for this answer
Sever21 [200]

Answer:

Leave the answer you’re looking for is C hope this helps

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
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