Find the product of two numbers whose sum is 11 and difference is 3.
1 answer:
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Answer:
-24 - 57i
Step-by-step explanation:
i'm assuming that this is a question about imaginary numbers and that i²= -1
we can expand the binomial by using the FOIL method (see attached)
(6 − 7i)(3 − 6i)
= (6)(3) + (6)(-6i) + (-7i)(3) + (-7i)(-6i)
=18 - 36i - 21i + 42i² (recall that i²= -1)
= 18 - 57i + 42(-1)
= 18 - 57i - 42
= -24 - 57i
