Commonly referred to as standard form:
2.4x10^5
<em><u>Question:</u></em>
Ana participated in a charity walk. She raised $0.25 for each 1/2 mile that she walked.The first day Ana walked 11 miles.The second day, she walked 14 miles.How much money did Ana raised?
<em><u>Answer:</u></em>
Ana raised $ 12.5
<em><u>Solution:</u></em>
From given question,
First day walk = 11 miles
Second day walk = 14 miles
<em><u>Let us first calculate the total distance she walked</u></em>
Total distance = first day walk + second day walk
Total distance = 11 + 14 = 25 miles
Thus she walked for 25 miles
Given that,
<em><u>She raised $0.25 for each 1/2 mile that she walked</u></em>

Therefore, for 1 mile we get,

Now calculate for 25 miles

Thus she raised $ 12.5
Answer:
A
Step-by-step explanation:
Given
2k² - k - 3
Consider the factors of the product of the k² term and the constant term which sum to give the coefficient of the k- term.
product = 2 × - 3 = - 6 and sum = - 1
The factors are + 2 and - 3
Use these factors to split the k- term
2k² + 2k - 3k - 3 ( factor the first/second and third/fourth terms )
= 2k(k + 1) - 3(k + 1) ← factor out (k + 1) from each term
= (2k - 3)(k + 1) → A
Answer:
if you mean 6/7ths, then the answer is 420$
Step-by-step explanation:
Answer:
b) 0.2961
c) 0.2251
d) Mean = 11.25, Standard deviation = 1.667
Step-by-step explanation:
We are given the following information:
We treat trucks undergoing a brake inspection passin as a success.
P( trucks undergoing a brake inspection passes the test) = 75% = 0.75
a) Conditions for binomial probability distribution
- There are n independent trial.
- Each trial have a success probability p
- The probability of success is same for all trials.
Then the number of trucks undergoing a brake inspection follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 15
b) P(proportion of groups will between 8 and 10 trucks pass the inspection)
We have to evaluate:
c) P( exactly 3 trucks fail the inspection)
p = 0.25
d) Mean and standard deviation
