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boyakko [2]
3 years ago
10

Suppose you asked 100 commuters how much they spend each year and obtained a mean of $167 spent on transportation and a standard

deviation of $40. Using the 2 SE rule of thumb, calculate a 95% confidence interval for the mean and select the values that come closest to those that would fill the spaces in the following interpretation: we can be 95% confident that the mean amount of money spent on transportation lies between _____ and _____ .
Mathematics
1 answer:
Lena [83]3 years ago
6 0

Answer:

The correct answer is "$159 and $175".

Step-by-step explanation:

The give values are:

Mean,

= $167

Standard deviation,

\sigma = $40

Number of commuters,

n = 100

Now,

⇒ SE=\frac{\sigma}{\sqrt{n} }

On putting the given values, we get

⇒       =\frac{40}{\sqrt{100} }

⇒       =\frac{40}{10}

⇒       =4

By using the 2 SE rule of thumb, we get

= $(167 - 2\times 4)

= 167-8

= 159 ($)

Or,

= (167 + 2\times 4)

= 167+8

= 175 ($)

i.e,

$159 and $175

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Viefleur [7K]

Answer: Option (c) is correct. Rate of interest = 6% p.a.

Step-by-step explanation:

Given that,

principal amount = $2000(loan)

time period =  284 days

interest amount (SI) = $93.37

we have to calculate the rate of interest (i),

Simple interest(SI) = principal amount × rate of interest (i) × time period

93.37 = 2000 × i × \frac{284}{365}

i = \frac{34080.05}{568000}

i = 0.06

i = 6%

3 0
3 years ago
What is the prime factorization of 420?
a_sh-v [17]

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Step-by-step explanation:

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2 years ago
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Please help me with this question.​
Stels [109]

Step-by-step explanation:

Mean of the origibal set = 20

No. of terms = 10

Sum = Mean x No. of terms

= 20 x 10 = 200

The sum of additional numbers to make the new set of observstion is 4 + 8 + 12...... + 40 = 220

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Whitepunk [10]

Answer:

NO, This Is A School Website ONLY Please Do NOT Post Such Things Here You Will Be Reported, And Your Answer Will Be Removed If This Continues Then Your Account Will Be Deleted.

7 0
2 years ago
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kotegsom [21]

Answer:

52

Step-by-step explanation:

A(2) + B(2) = C(2)

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AC + BD

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Hope this helps

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