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Elden [556K]
3 years ago
14

Hence explain x²-8x+20 is always positive

Mathematics
1 answer:
oee [108]3 years ago
3 0

Answer:

It is always positive because the discriminant is negative and therefore has no roots. This can also be interperted as the equation will always be above the x-axis on the parabola and therefore always be positive.

Step-by-step explanation:

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Plz Hurry I would Aprecate it
Irina18 [472]

Answer:

  B.  120 units³

Step-by-step explanation:

The area of the large white rectangle on the right represents the area of one of the larger surfaces of the prism. It appears to be (10 units) × (6 units), so has an area of 60 units². (You can count the squares there, if you like.)

That is adjacent to a gray area on the net that is 2 units wide, indicating that the prism is 2 units deep. Thus the volume is ...

  (60 units²) × (2 units) = 120 units³

4 0
4 years ago
n △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP. Find the area of △ABC if the area of △BMP is
monitta

Answer: The area of ABC is 56 m².

Explanation:

It is given that in △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP.

Since point P divides the line AB in 1:3, therefore the area of triangle APC and BPC is also in ratio 1:3. To prove this draw a perpendicular h on AB from C.

\frac{\text{Area of } \triangle BCP}{\text{Area of } \triangle ABC} =\frac{\frac{1}{2}\times BP\times CH}{\frac{1}{2}\times AB\times CH} =\frac{BP}{AB}= \frac{3}{4}

Since the area of BPC is \frac{3}{4}th part of total area, therefore area of APC is  \frac{1}{4}th part of total area.

The point M is the midpoint of CP, therefore the area of BMP and BMC is equal by midpoint theorem.

\text{Area of } \triangle BMP=\text{Area of } \triangle BMC

21=\text{Area of } \triangle BMC

Area of BPC is,

\text{Area of } \triangle BPC=\text{Area of } \triangle BMP+\text{Area of } \triangle BMC

\text{Area of } \triangle BPC=21+21

\text{Area of } \triangle BPC=42

Area of APC is,

\text{Area of } \triangle APC=\frac{1}{3}\times \text{Area of } \triangle BPC

\text{Area of } \triangle APC=\frac{1}{3}\times 42

\text{Area of } \triangle APC=14

Area of ABC is,

\text{Area of } \triangle ABC=\text{Area of } \triangle APC+\text{Area of } \triangle BPC

\text{Area of } \triangle ABC=14+42=56

Therefore, the area of ABC is 56 m².

5 0
4 years ago
Compare the following rational numbers with &gt; or &lt;..<br> -7.56 _____ -5.76
babunello [35]

Answer:

<

Step-by-step explanation:

-7.56 < -5.76

3 0
3 years ago
Read 2 more answers
The ratio of the number of left handers to the number of right handers in a middle school is 6:15. If there are 120 left handers
Zinaida [17]

Answer:

300

Step-by-step explanation:

there are 9 15's in 120 which means its going by 15's 3 x 5= 15 and if it says 6 that means its timesed by 2. 15 x 2= 30 then 30 x 10= 300

8 0
3 years ago
10x+20=7x-8<br><br> Solve for x.
Kazeer [188]

Step-by-step explanation:

Isolate the variable

10x - 7x = -20 - 8

3x = -28

x = -9.333333333333

5 0
3 years ago
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