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2 years ago

Solve the given quadratic equation. x^2=112

Mathematics

2 answers:

motikmotik2 years ago

4 0

Answer:

x=square root of 112

Step-by-step explanation:

to solve this equation we use inverse operations so we take the square root of 112 so x = √112

kykrilka [37]2 years ago

4 0

X=4√7 or
x=-4√7, that is what it equals.

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-4y+20=-x solve for y

melisa1 [442]

Answer:

y = x/4 + 5

Step-by-step explanation:

Solve for y:

20 - 4 y = -x

Hint: | Isolate terms with y to the left-hand side.

Subtract 20 from both sides:

-4 y = -x - 20

Hint: | Solve for y.

Divide both sides by -4:

Answer: y = x/4 + 5

5 0

3 years ago

Read 2 more answers

Find the remainder when f(x)=x3−4x2−6x−3 f ( x ) = x 3 − 4 x 2 − 6 x − 3 is divided by x+1

loris [4]

Answer:

The remainder is -2.

Step-by-step explanation:

According to the Polynomial Remainder Theorem, if we divide a polynomial P(x) by a binomial (x - a), then the remainder of the operation will be given by P(a).

Our polynomial is:

$P(x) = x^3-4x^2-6x-3$

And we want to find the remainder when it's divided by the binomial:

$x+1$

We can rewrite our divisor as (x - (-1)). Hence, a = -1.

Then by the PRT, the remainder will be:

$\displaystyle\begin{aligned} R &= P(-1)\\ &=(-1)^3-4(-1)^2-6(-1)-3 \\ &= (-1)-4(1)+(6)-3 \\ &= -2 \end{aligned}$

The remainder is -2.

5 0

2 years ago

Which equation is parallel to the line LaTeX: y=\frac{1}{2}x+3y = 1 2 x + 3and passes through the point (10, -5)?

sukhopar [10]

Answer:

$Equation\ of\ line:\ y=\frac{1}{2}x-10$

Step-by-step explanation:

$Let\ the\ required\ equation\ is\ y=mx+c\\\\where\ m\ is\ the\ slope\ of\ the\ equation\ and\ c\ is\ y-intercept\\\\It\ is\ parallel\ to\ the\ equation\ y=\frac{1}{2}x+3\\\\Hence\ slope\ of\ these\ two\ lines\ will\ be\ same.\\\\Slope\ of\ y=\frac{1}{2}x+3\ is\ \frac{1}{2}\\\\Hence\ slope\ of\ y=mx+c\ is\ \frac{1}{2}\Rightarrow m=\frac{1}{2}\\\\Equation:y=\frac{1}{2}x+c\\\\Line\ passes\ through\ (10,-5).\ Hence\ this\ point\ satisfies\ the\ equation\ of\ line.\\\\-5=\frac{1}{2}\times 10+c$