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Hitman42 [59]
3 years ago
6

In Ms.Martinez's library, 1/2 of the books are fiction.Of those fiction books,1/2 are realistic fiction.What fraction of the boo

ks in the library are realistic fiction?
Mathematics
1 answer:
Snowcat [4.5K]3 years ago
3 0

Andndmffmmfdfmfndbdbhdjddjdj

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Pleaseeeeee helpppppp 3^5/3^-4
Nataly_w [17]
I got 19,683. I hope this helps.

6 0
2 years ago
Quickly please I have like 7 minutes of class
Vinvika [58]

Answer:

the question is blurry take a picture again

Step-by-step explanation:

4 0
2 years ago
How do you send a picture for answering a question.
Nina [5.8K]
You have to upload it from your computer before you press "ADD YOUR ANSWER"
6 0
2 years ago
Draw two polygons that have corresponding angles that are all congruent but are not similar to prove that angle congruence is no
Marina86 [1]

There are infinitely many ways to do this. One such way is to draw a very thin stretched out rectangle (say one that is very tall) and a square. Example: the rectangle is 100 by 2, while the square is 4 by 4.

Both the rectangle and the square have the same corresponding angle measures. All angles are 90 degrees.

However, the figures are not similar. You cannot scale the rectangle to have it line up with the square. The proportions of the sides do not lead to the same ratio

100/4 = 25

2/4 = 0.5

so 100/4 = 2/4 is not a true equation. This numerically proves the figures are not similar.

side note: if you are working with triangles, then all you need are two pairs of congruent corresponding angles. If you have more than three sides for the polygon, then you'll need to confirm the sides are in proportion along with the angles being congruent as well.

3 0
3 years ago
SOMEONE HELP ME PLEASE
jenyasd209 [6]

Answer: The median, because the data distribution is skewed to the left

EXPLANATION

Given the box plot with the following parameters: 

Minimum value at 11

First Quartile, Q1 at 22.5

Median at 34.5

Third Quartile, Q3 at 36

Maximum value at 37.5

First, we notice that the data distribution is skewed to the left because the median (34.5) is closer to the third quartile (36) than to the first quartile

(22.5).

Furthermore, we know that the mean provides a better description of the center when the data distribution is symmetrical while the median provides a better description of the center when the data distribution is skewed.

Therefore, we conclude that for the given box plot, the median will provide a better description of the center because the data distribution is skewed to the left.

4 0
3 years ago
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