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elena-s [515]
2 years ago
15

What is 3 1/4: 1/4? How many 1/4's are there in 3 1/4?* O 3 O 1/4 13 O 12

Mathematics
2 answers:
GenaCL600 [577]2 years ago
8 0

Answer: 13

Step-by-step explanation:

erma4kov [3.2K]2 years ago
6 0

Answer:

13

Step-by-step explanation:

There are 12 1/4s in 3

Add the extra 1/4 + 13 1/4s

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If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.
Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

m∠SQT = m∠PQS  by Definition of congruency

m∠PQT = 2 × m∠SQT

Therefore;

(9·x + 34)° = 2 × (8·x - 25)° = (16·x - 50)°

Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

m∠SQT = (8·x - 25)°

Therefore;

m∠SQT = (8 × 12 - 25)° = 71°

m∠SQT = 71°

m∠PQT = 2 × m∠SQT

∴ m∠PQT = 2 × 71° = 142°

m∠PQT = 142°

m∠PQS = m∠SQT (Angles formed by the same bisector )

∴ m∠PQS = m∠SQT = 71°

m∠PQS = 71°

m∠SQR = m∠SQT + m∠TQR (Angle addition postulate)

m∠SQT = 71°

∴  m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

m∠TQR = 41°

Learn more about angles here:

brainly.com/question/2882938

#SPJ1

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1 year ago
Volume of a cube is 1728 cm3.Find its surface area​
Leno4ka [110]

Answer:

<h2>a=V⅓=1728⅓≈12</h2><h2 />

Step-by-step explanation:

<h2>Using the formula</h2><h2>V=a3</h2>

<h2>it is right answer </h2><h3>hope it will help you </h3>
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2 years ago
What’s this need help<br> asap !
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I need points and i’m using this bc you didn’t even give an equation
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What is the area of this quadrilateral?<br> 2 ft<br> 3 ft<br> 8 ft 8 ft<br> 3 ft<br> 2 ft
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Check the picture below.

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Write the decimal as a percent.<br> 0.487 = ??
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48.7%

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