Answer:
(B) 1
Step-by-step explanation:
g(x) = ∫₂ˣ f(t) dt
Use second fundamental theorem of calculus to find g'(x).
g'(x) = f(x) d(x)/dx − f(2) d(2)/dx
g'(x) = f(x)
g(x) is a maximum when g'(x) = 0.
0 = f(x)
x = 3
So the maximum value of g(x) is:
g(3) = ∫₂³ f(t) dt
g(3) = ½ (2) (1)
g(3) = 1
Angle 4: 98
Angle 3: 82
Angle 2: 98
This is true because 180-82 =98 meaning angle 2 and 4 are 98 leaving angle 3 to be 82
Hope this helps
Answer:
v
Step-by-step explanation:
