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Travka [436]
3 years ago
11

Describe the horizontal cross section of the triangular pyramid.

Mathematics
1 answer:
Gala2k [10]3 years ago
3 0
The cross section of this object would be A. Triangle
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(3/5 - 1/2) divided by 1/2 + 1.6 x (0.3 + 0.42)
MAVERICK [17]
1.202
3/5 and 1/2 can be 6/10 and 5/10. then 0.1/2 is 0.05. for the other part, just plug 0.72 x 1.6 into a calculator.

8 0
3 years ago
The diagonals of a rhombus are 6 inches and 8 inches. What is the perimeter of the rhombus?
loris [4]
The perimeter of the rhombus is 28 inches.
4 0
3 years ago
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How do you do this problem?
faust18 [17]

The volume of the original cylinder is

... V = π·r²·h

For r=1 and h=1, this is

... V = π·1²·1 = π

For the new cylinder, the volume is 1.089 times that amount.

... V = 1.089π = π·1.1²·(1-k)

... 1.089/1.21 = 1-k

... k = 1 - 1.089/1.21 = 1 - 0.9 = 0.1 = 10%

The appropriate choice is (B) 10.

7 0
4 years ago
Read 2 more answers
Yall know the anwser to this​
Olenka [21]

-1(-1-9)= -1*-10= 10

6 0
4 years ago
0.0176165803 is estimated to what
bezimeni [28]
It most common to round to the hundredths place, this is two spaces after the decimal. 

So look two spaces right - 0.17. If the third digit (in this case 6) is higher than 5 you round the number up if its not, keep it the same. 

"6" is greater than five, so round it to about (or approximately) 0.18.
5 0
4 years ago
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