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Stels [109]
3 years ago
9

A solution at 25 degrees Celsius is 1.0 × 10–5 M H3O+. What is the concentration of OH– in this solution? 1.0 × 10–5 M OH– 1.0 ×

10–14 M OH– 1.0 × 105 M OH– 1.0 × 10–9 M OH–
Chemistry
1 answer:
Fittoniya [83]3 years ago
5 0

Answer:

1.0 x 10⁻⁹ M OH⁻.

Explanation:

∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.

[H₃O⁺] = 1.0 x 10⁻⁵ M.

<em>∴ [OH⁻] = 10⁻¹⁴/[H₃O⁺] </em>= 10⁻¹⁴/(1.0 x 10⁻⁵ M) = <em>1.0 x 10⁻⁹ M.</em>

<em>So, the right choice is: 1.0 x 10⁻⁹ M OH⁻.</em>

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What is the total number of hydrogen atoms in a molecule of heptyne?
Step2247 [10]

Answer:

12

Explanation:

alkyne formula is CnH2n-2

heptyne = 7

6 0
3 years ago
g When 2.50 g of methane (CH4) burns in oxygen, 125 kJ of heat is produced. What is the enthalpy of combustion (in kJ) per mole
Anna [14]

Answer:

-800 kJ/mol

Explanation:

To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).

First, we have to calculate the moles of methane (CH₄) there are in 2.50 g of substance. For this, we divide the mass into the molecular weight Mw) of CH₄:

Mw(CH₄) = 12 g/mol C + (1 g/mol H x 4) = 16 g/mol

moles CH₄ = mass CH₄/Mw(CH₄)= 2.50 g/(16 g/mol) = 0.15625 mol CH₄

Now, we divide the heat released into the moles of CH₄ to obtain the enthalpy per mole of CH₄:

ΔHc = heat/mol CH₄ = 125 kJ/(0.15625 mol) = 800 kJ/mol

Therefore, the enthalpy of combustion of methane is -800 kJ/mol (the minus sign indicated that the heat is released).

3 0
2 years ago
How many liters of plasma are present in 8.5 pints?
stellarik [79]

Answer:

there are 4.0205 Litres of plasma in 8.5 pints

Explanation:

Recall that:

1 quart qt = 2 pints pt  and 1 quart = 946 mL

∴ two pints will contain 946 mL

and one pint will be = 946 mL/2

=  473 mL

Similarly, 8.5 pints will contain 473 mL × 8.5 = 4020.5  mL

We know that :

1000 mL = 1 Litres

Hence 4020.5 mL = (4020.5 /1000)L

= 4.0205 Litres

Therefore, there are 4.0205 Litres of plasma in 8.5 pints

4 0
3 years ago
A 3.50 amp power supply is used to deposit chromium from a solution of CrCl3. How long will it take to deposit 100.0 grams of ch
Norma-Jean [14]

Explanation:

The given data is as follows.

   Current (I) = 3.50 amp,        Mass deposited = 100.0 g

  Molar mass of Cr = 52 g

It is known that 1 faraday of electricity will deposit 1 mole of chromium. As 1 faraday means 96500 C and 1 mole of Cr means 52 g.

Therefore, 100 g of Cr will be deposited by "z" grams of electricity.

                z \times 52 g = 96500 \times 100 g

                         z = \frac{96500 \times 100 g}{52 g}

                            = 185576.9 C

As we know that, Q = I × t

Hence, putting the given values into the above equation as follows.

                      Q = I × t

           185576.9 C = 3.50 amp \times t  

                      t = 53021.9 sec

Thus, we can conclude that 100 g of Cr will be deposited in 53021.9 sec.

3 0
2 years ago
If an object increases in speed, it must be as a result of
zhenek [66]
DkskdjejisdjejkZjdjejasj
3 0
3 years ago
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