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2 years ago

12

If petrochemicals and ALL products made from them, suddenly disappeared last night, describe one drastic change in YOUR life tha

t would have negatively affected YOU PERSONALLY when you woke up this morning. Be specific.

1 answer:

EastWind [94]2 years ago

7 0

I hope you get a 100 on your assignment!

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The constant volume heat capacity of a gas can be measured by observing the decrease in temperature when it expands adiabaticall

miv72 [106K]

Answer:

The value is $C_p = 42. 8 J/K\cdot mol$

Explanation:

From the question we are told that

$\gamma = \frac{C_p }{C_v}$

The initial volume of the fluorocarbon gas is $V_1 = V$

The final volume of the fluorocarbon gas is $V_2 = 2V$

The initial temperature of the fluorocarbon gas is $T_1 = 298.15 K$

The final temperature of the fluorocarbon gas is $T_2 = 248.44 K$

The initial pressure is $P_1 = 202.94\ kPa$

The final pressure is $P_2 = 81.840\ kPa$

Generally the equation for adiabatically reversible expansion is mathematically represented as

$T_2 = T_1 * [ \frac{V_1}{V_2} ]^{\frac{R}{C_v} }$

Here R is the ideal gas constant with the value

$R = 8.314\ J/K \cdot mol$

So

$248.44 = 298.15 * [ \frac{V}{2V} ]^{\frac{8.314}{C_v} }$

=> $C_v = 31.54 J/K\cdot mol$

Generally adiabatic reversible expansion can also be mathematically expressed as

$P_2 V_2^{\gamma} = P_1 V_1^{\gamma}$

=> $[ 81.840 *10^3] [2V]^{\gamma} = [202.94 *10^3] V^{\gamma}$

=> $2^{\gamma} = 2.56$

=> $\gamma = 1.356$

So

$\gamma = \frac{C_p}{C_v} \equiv 1.356 = \frac{C_p}{31.54}$

=> $C_p = 42. 8 J/K\cdot mol$

3 0

3 years ago

What are three things that are considered a chemical change

kodGreya [7K]

Answer:

Color change, precipitation, bubbling

Explanation:

Chemical change changes the chemical composition and undergoes a process in which it results as a new substance.

8 0

2 years ago

Hep balance equation

Lena [83]

Answer:

4, 3, 1, 12

It balances now

3 0

3 years ago

Which best demonstrates an example of the common ion effect?

ella [17]

Answer: A. The compound CuCl is 500 times less soluble in sea water than it is in pure water.

pure water.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in a equilibrium reaction, the equilibrium will shift in a direction so as to minimize the effect.

Thus when a common ion is introduced to an equilibrium reaction, the equilibrium will shift in a direction where the concentration of common ion is decreasing.

$CuCl\rightleftharpoons Cu^++Cl^-$

$NaCl\rightarrow Na^++Cl^-$

When common ion such as $Cl^-$ from NaCl in sea water is introduced to an equilibrium reaction, the equilibrium will shift in a direction where the concentration of common ion is decreasing i.e. in the left side and thus solubility of CuCl further decreases.

6 0

3 years ago

According to the law of conservation of momentum, what is the momentum of the object after the collision? 4,500 g · m/s 1,750 g

Genrish500 [490]

Answer:

C. 1,500 kg · m/s

5 0

3 years ago