Heat can be transferred from one material to another by direct touch (conduction), by differences in density of a fluid (temperature difference), and by RADIATION
Answer:
7- 0.69 moles.
8- El nuevo volumen es 3.8L.
Explanation:
7- Usando la ley general de los gases:
PV = nRT
PV / RT = n
<em>P es presión = 1.10atm</em>
<em>V es volumen = 15.70L</em>
<em>R es constante de los gases = 0.082atmL/molK</em>
<em>T es temperatura absoluta = 31°C + 273.15K = 304.15K</em>
<em />
Reemplazando:
1.10atm*15.70L / 0.082atmL/molK*304.15K = n
<h3>0.69 moles</h3><h3 />
8- La ley combinada de los gases establece como ecuación:
P1V1 / T1 = P2V2 / T2
<em>Donde P1 es la presión inicial = 760mmHg</em>
<em>V1 volumen inicial = 2L</em>
<em>T1 es temperatura absoluta = 273.15 + 27 = 300.15K</em>
<em>P2 = 380mmHg</em>
<em>T2 = 12°C + 273.15 = 285.15K</em>
<em />
Reemplazando:
760mmHg*2L / 300.15K = 380mmHg*V2 / 285.15K
3.8L = V2
<h3>El nuevo volumen es 3.8L</h3>
Answer:
4.254320865115cm or simplied 4.25cm
Explanation:
Answer:
The aroma from a lighted scented candle is released through the evaporation of the fragrance from the hot wax pool and from the solid candle itself. Like unscented candles, properly-formulated scented candles will primarily produce water vapor and carbon dioxide when burned
Explanation:
Answer:
1. The pressure will be 32 atm, twice the initial pressure.
2. The pressure will be 1.83 atm, one third of the initial pressure.
Explanation:
Boyle's law is one of the gas laws that relates the volume and pressure of a certain quantity of gas kept at a constant temperature.
This law says that "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure." This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.
Boyle's law is expressed mathematically as:
Pressure * Volume = constant
or P * V = k
Ahora es posible suponer que tienes un cierto volumen de gas V1 que se encuentra a una presión P1 al comienzo del experimento. Si varias el volumen de gas hasta un nuevo valor V2, entonces la presión cambiará a P2, y se cumplirá:
P1*V1=P2*V2
1. In this case:
- P1= 16 atm
- V1
- P2= ?
- V2= V1÷2=
because the volume is halved.
So:
16 atm*V1= P2* 
Solving:
=P2
16 atm*2= P2
32 atm= P2
<u><em>The pressure will be 32 atm, twice the initial pressure.</em></u>
2. Now
- P1= 5.5 atm
- V1
- P2= ?
- V2= V1*3 because the volume is tripled.
So:
5.5 atm*V1= P2* V1*3
Solving:
=P2
= P2
1.83 atm= P2
<u><em>The pressure will be 1.83 atm, one third of the initial pressure.</em></u>