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barxatty [35]
3 years ago
15

Which term refers to the movement of materials through a cell membrane when the cell’s energy is required?                      

                                                                                                                                                                                                                                                           A) active transport B) passive transport C) diffusion D) osmosis
Chemistry
1 answer:
Mumz [18]3 years ago
6 0
The answer to this is A.
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Heat can be transferred from one material to another by direct touch, by differences in density in a fluid, and by ______ conduc
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Heat can be transferred from one material to another by direct touch (conduction), by differences in density of a fluid (temperature difference), and by RADIATION
7 0
2 years ago
7-¿Cuántos moles de CO2 estarán encerrados en un recipiente metálico a una presión de 1.10 Atm. y una temperatura de 31 °C, sabi
Aleks [24]

Answer:

7- 0.69 moles.

8- El nuevo volumen es 3.8L.

Explanation:

7- Usando la ley general de los gases:

PV = nRT

PV / RT = n

<em>P es presión = 1.10atm</em>

<em>V es volumen = 15.70L</em>

<em>R es constante de los gases = 0.082atmL/molK</em>

<em>T es temperatura absoluta = 31°C + 273.15K = 304.15K</em>

<em />

Reemplazando:

1.10atm*15.70L / 0.082atmL/molK*304.15K = n

<h3>0.69 moles</h3><h3 />

8- La ley combinada de los gases establece como ecuación:

P1V1 / T1 = P2V2 / T2

<em>Donde P1 es la presión inicial = 760mmHg</em>

<em>V1 volumen inicial = 2L</em>

<em>T1 es temperatura absoluta = 273.15 + 27 = 300.15K</em>

<em>P2 = 380mmHg</em>

<em>T2 = 12°C + 273.15 = 285.15K</em>

<em />

Reemplazando:

760mmHg*2L / 300.15K = 380mmHg*V2 / 285.15K

3.8L = V2

<h3>El nuevo volumen es 3.8L</h3>
4 0
2 years ago
AN object has a volume<br> of 77ml and a mass of<br> 429. What is the density<br> of this object?
pantera1 [17]

Answer:

4.254320865115cm or simplied 4.25cm

Explanation:

6 0
3 years ago
How are scented candles made?
marysya [2.9K]

Answer:

The aroma from a lighted scented candle is released through the evaporation of the fragrance from the hot wax pool and from the solid candle itself. Like unscented candles, properly-formulated scented candles will primarily produce water vapor and carbon dioxide when burned

Explanation:

7 0
2 years ago
Read 2 more answers
1. If you have a sample of gas at a pressure of 16 atm, what will the pressure be if the volume is halved?
vagabundo [1.1K]

Answer:

1. The pressure will be 32 atm, twice the initial pressure.

2. The pressure will be 1.83 atm, one third of the initial pressure.

Explanation:

Boyle's law is one of the gas laws that relates the volume and pressure of a certain quantity of gas kept at a constant temperature.

This law says that "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure." This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

or P * V = k

Ahora es posible suponer que tienes un cierto volumen de gas V1 que se encuentra a una presión P1 al comienzo del experimento. Si varias el volumen de gas hasta un nuevo valor V2, entonces la presión cambiará a P2, y se cumplirá:

P1*V1=P2*V2

1. In this case:

  • P1= 16 atm
  • V1
  • P2= ?
  • V2= V1÷2= \frac{V1}{2} because the volume is halved.

So:

16 atm*V1= P2* \frac{V1}{2}

Solving:

\frac{16 atm*V1*2}{V1}=P2

16 atm*2= P2

32 atm= P2

<u><em>The pressure will be 32 atm, twice the initial pressure.</em></u>

2. Now

  • P1= 5.5 atm
  • V1
  • P2= ?
  • V2= V1*3 because the volume is tripled.

So:

5.5 atm*V1= P2* V1*3

Solving:

\frac{5.5 atm*V1}{3*V1}=P2

\frac{5.5 atm}{3}= P2

1.83 atm= P2

<u><em>The pressure will be 1.83 atm, one third of the initial pressure.</em></u>

7 0
2 years ago
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