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Sindrei [870]
3 years ago
6

What are the two forces that battle within a star ?

Chemistry
2 answers:
Kay [80]3 years ago
5 0

Gravity and Thermal pressure

zimovet [89]3 years ago
5 0
Pressure and gravity
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If a tube contains 2.0oz of sunscreen, how many kilograms of benzyl salicylate are needed to manufacture 325 tubes of sunscreen
Vadim26 [7]

<u>Answer:</u>

Now it is given here that there are 325 tubes that are manufactured for sunscreen. And we also know that the percentage of sunscreen in benzyl salicylate is 2.5% here in one tube we have 2 Oz of sunscreen.

<u>Explanation:</u>

So sunscreen in 325 tubes will be 2 x 325= 650 Oz. Since we know the amount of sunscreen in 325 tubes the amount of Benzyl salicylate in all 325 tubes will be 650 x 0.025 = 16.25 Oz

<em>Now this can be converted into kg as 0.46 kg</em>.

4 0
3 years ago
What Can bond together to form an ionic bond?
Kazeer [188]

Answer:

An ionic bond forms between two ions of opposite charges. In ionic bonding, electrons transfer from one atom to another. The elements take on either a negative or positive charge. Ions are another name for charged atoms. Some elements are electropositive, and some are electronegative.

Hope this helps!

5 0
3 years ago
Consider the group a1 element sodium atomic number 11, the group 3a element aluminum atomic number 13, and the group 7a element
Akimi4 [234]
According to there chemical properties
7 0
3 years ago
Standard reduction half-cell potentials at 25∘c half-reaction e∘ (v) half-reaction e∘ (v) au3 (aq) 3e−→au(s) 1.50 fe2 (aq) 2e−→f
Zanzabum

<em>K</em> = 5.0 × 10^25

<h2>Part (a). Calculate <em>E</em>° for the reaction </h2>

<em>Step 1.</em> Write the equations for the two half-reactions

2H^(+)(aq) + 2e^(-) → H2(g); _0.00 V

Zn^(2+)(aq) + 2e^(-) → Zn(s); -0.76 V

<em>Step 2.</em> Identify the cathode and the anode

The half-cell with the more negative <em>E</em>° (Zn) is the anode.

<em>Step 3.</em> Calculate <em>E</em>°

Zn(s) → Zn^(2+)(aq) + 2e^(-); _________+0.76 V

2H^(+)(aq) + 2e^(-) → H2(g); __________0.00 V

Zn(s) + 2H^(+)(aq) → Zn^(2+)(aq) + H2(g); +0.76 V

<em>E</em>° = +0.76 V

<h2>Part (b). Calculate <em>K</em> for the reaction </h2>

The relation between <em>E</em>° and <em>K</em> is

<em>E</em>° = (<em>RT</em>)/(<em>nF</em>)ln<em>K </em>

where

<em>R</em> = the universal gas constant: 8.314 J·K^(-1)mol^(-1)

<em>T</em> = the Kelvin temperature

<em>n</em> = the moles of electrons transferred

<em>F</em> = the Faraday constant: 96 485 J·V^(-1)mol^(-1)

Then

0.76 V = [8.314 J·K^(-1)mol^(-1) × 298.15 K]/[2 × 96 485 J·V^(-1)mol^(-1)]ln<em>K</em>

0.76 = 0.012 85 ln<em>K</em>

ln<em>K</em> = 0.76/0.012 85 = 59.16

<em>K</em> =e^59.16 = 5.0 × 10^25

4 0
3 years ago
The conversion of 37 ˚C to K
77julia77 [94]

Answer:

310.15

Explanation:

c + 273.15 = k

37+ 273.15 = 310.15

8 0
3 years ago
Read 2 more answers
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