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Yuliya22 [10]
3 years ago
10

Why does a bowling ball and a feather hit the ground at the same time when they are dropped in a vacuum?

Physics
1 answer:
AnnyKZ [126]3 years ago
8 0

Answer:

See the explanation below.

Explanation:

This is because the vacuum chamber removes all the air contained and for this reason, there is no force that opposes the movement of the feather when falling. We must remember that the free fall equation of kinematics is not a function of the mass of an object.

v_{f} =v_{o} +g*t

where:

Vf = final velocity [m/s]

Vo = initial velocity [m/s]

g = gravity acceleration [m/s²]

t = time [s]

As we can see the mass of the object is not included in the equation.

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A long wire carrying I=1.1A of constant current oriented North-to-South (and the current is running northwards) is placed horizo
Tema [17]

Answer:

The absolute value of the angular deviation is 39.3°.

Explanation:

Given that,

Current = 1.1 A

Distance = 0.9 cm

Magnetic field = 20μT

We need to calculate the magnetic field due to wire

Using formula of magnetic field

B=\dfrac{\mu_{0}I}{2\pi d}

Put the value into the formula

B=\dfrac{4\pi\times10^{-7}\times1.1}{2\pi\times0.9\times10^{-2}}

B=24.4\times10^{-6}\ T

B=24.4\ \mu T

We need to calculate the absolute value of the angular deviation

Using formula of direction

\theta=\tan^{-1}(\dfrac{B_{E}}{B_{w}})

\theta=\tan^{-1}(\dfrac{20 \mu}{24.4 \mu})

\theta=39.3^{\circ}

Hence, The absolute value of the angular deviation is 39.3°.

5 0
3 years ago
What is the power dissipated by a 50.0 ohm resistor?
Morgarella [4.7K]

Answer:

The power, in watts, dissipated as heat in a resistor varies jointly with the resistance, in ohms, and the square of the current, in amperes. A 15-ohm resistor carrying a current of 1 ampere dissipates 15 watts. How much power is dissipated in a 5-ohm resistor carrying a current of 3 amperes?

Explanation:

6 0
3 years ago
A steel rope is used to lift a 26 kg slab of concrete from the ground to a height of 20 m. Assume that the rope moves the concre
Ne4ueva [31]

Answer:

5200 Joules

Explanation:

Work Formula:

W = F . D

W = (26.10) . 20

W = 260 . 20

W = 5200 Joules

5 0
3 years ago
3 A rocket of mass 1200 kg is travelling at 2000 m/s. It fires its engine for 1 minute. The forward thrust provided by the rocke
natita [175]

The impulse shared by the object equals the difference in momentum of the object. In equation form,

F • t = m • Δ v. In a collision, objects experience an impulse; the impulse causes and is equal to the difference in momentum.

<h3>How to calculate  thrust provided by the rocket engines is 10 kN (10 000 N).?</h3>

a)There is this impulse-momentum change equation.

where m$ is the mass of a body, $F$ is a force acting to the body, $t$ is time and $D E L A T A N\}=V_{2}-V_{1}$ is the change of velocity.We consider everything is happen along a straight line, and gravitation does not participate.So, the increase of momentum is $\mathrm{F}^{*} \mathrm{t}=10000 \mathrm{~N} * 60$ seconds $=600000 \mathrm{~N}^{*} \mathrm{~s}=600000\left(\mathrm{~kg}^{*} \mathrm{~m}\right)^{*} \mathrm{~s} / \mathrm{s}^{\wedge} 2=600000 \mathrm{~kg}{ }^{*} \mathrm{~m} / \mathrm{s}$.

We consider everything exits happen along a straight line, and gravitation does not participate.

So, the increase of momentum is F×t = 10000 N × 60 seconds = 600000 N*s = 600000 (kg*m)*s/s^2 = 600000 kg*m/s.

$$\Delta(\mathrm{V})=\frac{\mathrm{F.t}}{\mathrm{m}}=\frac{600000}{1200}=500 \mathrm{~m} / \mathrm{s} .$$

New velocity after  engine was firing during 60 seconds is 2000 + 500 = 2500 m/s.

To learn more about Impulse-momentum, refer

brainly.com/question/20586658

#SPJ9

5 0
2 years ago
Two tiny, spherical water drops, with identical charges of −8.00 ✕ 10^(−17) C, have a center-to-center separation of 2.00 cm.
Damm [24]

Answer:

F=1.4384×10⁻¹⁹N

Explanation:

Given Data

Charge q= -8.00×10⁻¹⁷C

Distance r=2.00 cm=0.02 m

To find

Electrostatic force

Solution

The electrostatic force between between them can be calculated from Coulombs law as

F=\frac{kq^{2} }{r^{2} }

Substitute the given values we get

F=\frac{(8.99*10^{9} )*(-8.00*10^{-17} )^{2} }{(0.02)^{2} }\\ F=1.4384*10^{-19} N

7 0
3 years ago
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