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Hoochie [10]
3 years ago
10

8 kg cat is running with a velocity of 4 m/s. What is the cat's momentum?

Physics
1 answer:
Svetllana [295]3 years ago
4 0

Answer:

Kinetic energy = (1/2) (mass) (speed)²

Kinetic energy = (1/2) (8 kg) (4 m/s)² =

 

                                 (4 kg) (16 m²/s²) =

                                  64  (kg-m/s²) (m) = 64 newton-m = 64 joules

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Can anybody answer this question. Please...
Nady [450]
Yes they acquire both poles. Each side facing each other should be opposites
So A is N
C is S
D is N
B is S
8 0
3 years ago
A shopper pushes a grocery cart for a distance of 18m at a constant speed on level ground, against a 37.5N frictional force. he
goldfiish [28.3K]

d = distance to which the grocery cart is pushed = 18 m

f = frictional force = 37.5 N

θ = angle of force below the horizontal = 27.5 deg

W = gravitational force in downward direction

Θ = angle between gravitational force in down direction and displacement in horizontal direction = 90

U = work done on the cart by gravitational force

work done on the cart by gravitational force is given as

U = W d CosΘ

inserting the values

U = W (18) Cos90

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5 0
3 years ago
When a sound source approaches you, how does the pitch change?
torisob [31]

Answer:

The pitch increases

Explanation:

This effect is called Doppler effect. Doppler effect occurs when the source of a wave (such as a sound wave) moves relative to a stationary observer. In particular, two situations can occur:

- When the sound source moves towards the observer, there is a decrease in the apparent wavelength as seen from the observer; since frequency is inversely proportional to wavelength, the observer hears a sound with apparent higher frequency, which corresponds to a higher-pitch sound.

- When the sound source moves away from the observer, there is an increase in the apparent wavelength as seen from the observer; since frequency is inversely proportional to wavelength, the observer hears a sound with apparent lower frequency, which corresponds to a lower-pitch sound.

In this case, the sound source is approaching you: so we are in the 1st situation, therefore the pitch of the sound increases.

5 0
3 years ago
Read 2 more answers
Technician A says that cooling fans are designed to draw air through the radiator to aid in the heat transfer process. Technicia
miskamm [114]

Answer:

The correct answer is (A)

Explanation:

Cooling fans are designed to move air through the radiator, this airflow removes heat from the coolant created by the engine using the radiator as a conductor.

These fans are featured in both front and rear-wheel drive vehicles and are activated by a coolant sensor.

All engines have a preferred operating temperature which requires a warm-up period to operate at peak efficiency. When cooling fan operation fails, it will cause the engine coolant to retain heat, forcing the engine to get overheat.

I hope it helps!

7 0
3 years ago
Applying a constant net force to an object causes it to accelerate at 10 m/s2. What will the acceleration of the object be if (a
zalisa [80]

Explanation:

F=ma

The force is directly proportional to mass and acceleration.

a) If force is doubled then acceleration is doubled.

b) If mass is halved then acceleration of the will increase if the force is constant.

c) If the force is doubled and the mass is doubled then acceleration is halved.

F_1=m_1a_1\\\Rightarrow a_1=\frac{F_1}{m_1}

2F_1=2(2m_1)a_2\\\Rightarrow F_1=2m_1a_2\\\Rightarrow a_2=\frac{F_1}{2m_1}

Dividing the equation

\frac{a_1}{a_2}=\frac{\frac{F_1}{m_1}}{\frac{F_1}{2m_1}}\\\Rightarrow a_2=\frac{1}{2}a_1

d) If the force is doubled and the mass is halved then acceleration is doubled

F_1=m_1a_1\\\Rightarrow a_1=\frac{F_1}{m_1}

2F_1=2(\frac{m_1}{2})a_2\\\Rightarrow a_2=2\frac{F_1}{m_)}\\\Rightarrow a_2=\frac{F_1}{2m_1}

e) If the force is halved then the acceleration is halved.

f) If the mass is doubled then the acceleration is halved keeping the constant force

g) If the force is halved and the mass is halved then the acceleration is doubled

F_1=m_1a_1\\\Rightarrow a_1=\frac{F_1}{m_1}

\frac{1}{2}F_1=\frac{1}{2}(\frac{m_1}{2})a_2\\\Rightarrow a_2=2\frac{F_1}{m_1}

h) If the force is halved and the mass is doubled then the acceleration is halved.

F_1=m_1a_1\\\Rightarrow a_1=\frac{F_1}{m_1}

\frac{1}{2}F_1=\frac{1}{2}(2m_1)a_2\\\Rightarrow a_2=\frac{F_1}{2m_1}

7 0
3 years ago
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