Answer:
<em>One mole of anything is 6.022×1023 everythings, including atoms. Multiply the moles Fe by 6.022×1023 atoms/mol. 3.77mol Fe ×6.022×1023atoms Fe1mol Fe =2.27×1024 atoms Fe rounded to three significant figures.</em>
Answer:
I think your answer is either b or c but I think b is more likely to be your answer
Answer:
The correct answer would be - 2.4KJ or, 2400J
Explanation:
Given:
heat capacity of liquid water - 4.18 J/g·°C
heat of vaporization - 40.7 kJ/mol
Mass of water = 1g
Moles of water = mass/molar mass
= 1g/18.016g
= 0.055 moles
Then,
Total heat required = q1(to raise the temperature to 100) + q2(change from the liquid phase to gas/steam)
= m *s*dt + moles * heat of vaporization
= (1g * 4.18 j/gc * (100-67)) + 0.055* 40.7 KJ
= 137.94J + 2.26KJ
=0.138KJ + 2.26KJ
=2.4KJ or, 2400J
Thus, the correct answer would be - 2.4KJ or, 2400J