Sodium oxide and carbon dioxide
Explanation:
When sodium carbonate decomposes sodium oxide and carbon dioxide is produced:
Na₂CO₃ → Na₂O + CO₂
- This kind of reaction is known as decomposition reaction.
- In a decomposition reaction,
- In this kind of reaction, two or more products form from a single reactant.
- The breakdown of a compound into its component individual elements or other compounds falls into this reaction category.
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Answer:
characteristics i believe
Answer:
1. 4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2
2. 6 moles of Cl2
Explanation:
1. The balanced equation for the reaction. This is illustrated below:
4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2
2. Determination of the number of mole of Cl2 produce when 4 moles of FeCl3 react with 4 moles. To obtain the number of mole of Cl2 produced, we must determine which reactant is the limiting reactant.
This is illustrated below:
From the balanced equation above,
4 moles of FeCl3 reacted with 3 moles of O2.
Since lesser amount of O2 (i.e 3 moles) than what was given (i.e 4 moles) is needed to react completely with 4 moles of FeCl3, therefore FeCl3 is the limiting reactant and O2 is the excess reactant.
Finally, we can obtain the number of mole Cl2 produced from the reaction as follow:
Note: the limiting reactant is used as it will produce the maximum yield of the reaction since all of it is used up in the reaction.
From the balanced equation above,
4 moles of FeCl3 will react to produced 6 moles of Cl2.
Answer:
P1V1/T1= P2V2/T2
Explanation:
Combined gas law involves Boyle's law and Charles law altogether with the formula of Boyle's law as P1V1=P2V2
formula for charles law as V1/T1=V2/T2
so when combined form P1V1/T1=P2V2/T2