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3 years ago

Please someone help I need the answers today

Mathematics

1 answer:

vichka [17]3 years ago

3 0

Answer:

Step-by-step explanation:

M angle A equals 130 degrees, M angle B equals 50 degrees and M angle C equals 130 degrees. key words to remember is interior, exterior and corresponding angles.

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Is anyone good with this? I need help finding the answer.

scoray [572]

Answer:

parallel:

$7x - 8y = 60$

perpendicular:

$8x + 7y = 4$

Step-by-step explanation:

original line:

-7x + 8y = 4

m = 7/8

parallel:

m = 7/8

L: 7x - 8y = k

(4, -4) -> L

28 + 32 = 60 = k

L: 7x - 8y = 60

perpendicular:

m = -8/7

L: -8x + 7y = k

(4, -4) -> L

-32 + 28 = -4 = k

L: -8x -7y = -4

=> 8x + 7y = 4

7 0

3 years ago

10. Solve using substitution. x - 2y = 3 3x + y = -5

nasty-shy [4]

Move all terms that don't contain x to the right side and solve.

x=−5/3−y/3

plz mark me as brainliest :)

5 0

3 years ago

PLS SOMEONE HELP ME ASAP

babymother [125]

Answer:

A. (2i)(8) = d. 16i

B. 16i³ = b. -16i

C. (2i)⁴ = a. 16

D. (2i)(8i) = c. -16

Step-by-step explanation:

A. Multiply 2i by 8 to get 16i, which corresponds to d.

B. The exponent is 3 more than a mulitple of 4 in 16i³, so the answer is negative. -16i corresponds to b.

C. (2i)⁴ has an exponent that is a multiple of 4, so the i isn't needed. 16 corresponds to a.

D. (2i)(8i) simplifies to 2(8) * i². The exponent is 2 more than a multiple of 4, so the answer is negative, without an i. -16 corresponds to c.

8 0

3 years ago

Assume that the national credit card interest rate is 12.83 percent. A study of 62 college students finds that their average int

meriva

Answer:

b) 95 percent confidence interval for this single-sample t test

[11.64, 16.36]

Step-by-step explanation:

Explanation:-

Given data a study of 62 college students finds that their average interest rate is 14 percent with a standard deviation of 9.3 percent.

Sample size 'n' =62

sample mean x⁻ = 14

sample standard deviation 'S' = 9.3

95 percent confidence interval for this single-sample t test

The values are $(x^{-} - t_{0.05} \frac{S}{\sqrt{n} } ,x^{-}+t_{0.05}\frac{S}{\sqrt{n} })$ the 95 percent confidence interval for the population mean 'μ'