What is the measure of angle A'B'C?
1 answer:
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Solve for n.
21k−3n+9p>3p+12
Add -21k to both sides.
21k−3n+9p+−21k>3p+12+−21k
−3n+9p>−21k+3p+12
Add -9p to both sides.
−3n+9p+−9p>−21k+3p+12+−9p
−3n>−21k−6p+12
Divide both sides by -3.
−3n/−3 > −21k−6p+12/−3
n < 7k+2p−4
21k−3n+9p>3p+12
Add -21k to both sides.
21k−3n+9p+−21k>3p+12+−21k
−3n+9p>−21k+3p+12
Add -9p to both sides.
−3n+9p+−9p>−21k+3p+12+−9p
−3n>−21k−6p+12
Divide both sides by -3.
−3n/−3 > −21k−6p+12/−3
n < 7k+2p−4