Lets solve the equation first:
<span> 0.5 – |x – 12| = –0.25
</span>= 1/2 - |x - 12| = -1/4
= 2 - 4<span>|x - 12| = -1
= 4|x - 12| = 3
= |x - 12| = 0.75
positive case, x >= 12
x - 12 = 0.75
x = 12.75
negative case, x < 12
x - 12 = -0.75
x = 11.25
So those are the two solutions.
These apply:
</span>1.) The equation will have no solutions.
2.) A good first step for solving the equation is to subtract 0.5 from both sides of the equation.
<span>3.) A good first step for solving the equation is to split it into a positive case and a negative case.
</span><span>5.) The negative case of this equation is x – 12 = –0.75.</span>
Answer:
2 (real) solutions.
Step-by-step explanation:
A quadratic always has two solutions, whether they are real or complex.
Sometimes the solution is complex, involving complex numbers (2 complex), sometimes they are real and distinct (2 real), and sometimes they are real and coincident (still two real, but they are the same).
In the case of
x^2+3x = 3, or
x² + 3x -3 = 0
we apply the quadratic formula to get
x = (-3 +/- sqrt(3^2+4(1)(3))/2
to give the two solutions
{(sqrt(21)-3)/2, -(sqrt(21)+3)/2,}
both of which are real.
Answer:
Both would work.
Step-by-step explanation:
If we call Jackie's apples a, then Mark has a - 4 apples. Therefore, together they have a + (a - 4) apples, and we know that they have a total of 12 apples so we can write a + (a - 4) = 12 to represent the situation. On the other hand, if Mark has a apples, then Jackie has a + 4 apples, so we can also write a + (a + 4) = 12 to represent the situation as well. Therefore, both of the equations would work. Hope this helps!
<span>1 and 2/3 time 1 and 1/3 is 2.22222222222 which rounds to 2.</span>
