All categories

3 years ago

The diameter of a circular garden is 22 feet. What is the approximate area of the shaded region

Mathematics

2 answers:

SOVA2 [1]3 years ago

7 0

Answer:

Step-by-step explanation:

The radius it .5 of the diameter so in this case the radius is 11. The formula for area is pi*r^2= pi*11^2=pi*121=380.13

andrew-mc [135]3 years ago

4 0

<h2>Answer:</h2>

<h2>Step-by-step explanation:</h2>

Area of a circle is given by

A = π r ²

Area = 3.14 * 11²

Area = 3454 feet²

You might be interested in

What's 5.17÷186 ? The directions for the assignment that I was forced to do is above.

My name is Ann [436]

0.0277956989 I really hope this helps you out!

7 0

3 years ago

Nicolas has three fewer than twice the number of songs downloaded as Sabrina does.

Alla [95]

The expression 2x-3 represent's: The number of songs downloaded by Nicholas.
The variable x represents: The number of songs downloaded by Sabrina.

5 0

2 years ago

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

2 years ago

How to solve 2x-1/2=3-x

ValentinkaMS [17]

To solve for x:
Move all the terms containing "x" to the left side of the equation. Do this by adding x to both sides.

2x+x=3x. The new equation is:
3x-1/2=3

Now, move all terms not containing "x" to the right side of the equation. Do this by adding 1/2 to both sides.
3x=3+1/2 The new equation is:
3x=3 1/2, or 3.5

The final step is to isolate x. To do so, divide each side by 3.
3x/3 = 3 1/2 /3 The new equation is:
x=1 1/6

5 0

3 years ago

The following spinner will be spun and a coin will be flipped. If Audrey spins the spinner once and flips the coin once, then cr

Papessa [141]

Answer:

I cant help if there is not a picture of the spinner because I dont know how many sections are there.

Step-by-step explanation:

3 0

3 years ago