The result of the subtraction of 4365 and 3412 using octal numbers is of:
753.
<h3>What are octal numbers?</h3>
For octal numbers, each number is represented by three bits, as follows:
Then the binary representation of number 4365 is given as follows:
100011110101
The binary representation of number 3412 is given as follows:
011100001010
Then the following binary subtraction is made:
100011110101 - 011100001010
The result of this subtraction is of:
100011110101 - 011100001010 = 111101011
Then the octal result is given as follows:
111 101 011 = 753.
More can be learned about binary numbers at brainly.com/question/8649831
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Its either called an HDD or an SSD
The default custom dictionary is the dictionary to which Microsoft Word adds the word when you do this.
Answer:
Following are the program in the Python Programming Language:
def check(num): #define function
if(num.isdigit()): #set if statement
return "yes"; #return yes if condition is true
else:
return "no";# return no if condition is false
string=input("Enter the numbers 0-9: ") #get input from the user
print(check(string)) #print and call the function
Output:
Enter the numbers 0-9: 1995
yes
Enter the numbers 0-9: 42,000
no
Explanation:
Here, we define a function "check()" and pass an argument in its parameter "num" inside the function.
- we set if-else conditional statement and check the value stored in the variable "num" is the digit by using built in function "isdigit()" then return "yes".
- Then, otherwise it return "no".
Finally, we get the input from the user in the variable "string" then, we call the function through "print()" function.
The answer is <span> tunnel mode encryption. This</span><span> describes encryption that protects the entire original ip packet's header and payload. A tunnel mode encryption </span><span>protects the internal routing information by encrypting the IP header of the original packet. The original packet is encapsulated by a another set of IP headers. .<span>Additional headers are added to the packet; so the payload MSS is less.</span></span>
