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taurus [48]
3 years ago
5

When sodium azide is activated in an automobile airbag, nitrogen gas and sodium are produced according to the following equation

: 2NaN3(s) ⟶ 2Na(s) + 3N2(g) If 0.500 mol NaN3 react, what mass in grams of nitrogen would result?
A) 21.0 g N2
B) 20.0 g N2
C) 19.0 g N2
D) 12.0 g N2
Mathematics
1 answer:
klasskru [66]3 years ago
7 0
Answer:
A) 21.0 g of N2

Explanation:
From the periodic table:
atomic mass of nitrogen = 14 grams
This means that:
molar mass of N2 = 2(14) = 28 grams/mole

Now, from the given balanced equation, 2 moles of NaN3 produce 3 moles of N2. We can use cross multiplication to know the number of moles of N2 produced from 0.5 moles of NaN3 as follows:
2 moles NaN3 ..............> 3 moles N2
0.5 moles NaN3 ...........> ?? moles N2
number of moles of N2 = (0.5*3) / 2 = 0.75 moles

Now, we will get the mass of 0.75 moles as follows:
number of moles = mass / molar mass
mass = number of moles * molar mass
mass = 0.75 * 28
mass = 21 grams

Hope this helps :)
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Step-by-step explanation:

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Tpy6a [65]

Answer:

56

Step-by-step explanation:

Cube root of 175616 by prime factorization method is 56

Solution:

To find cube root of 175616 by prime factorization method

A number that must be multiplied by itself three times to equal a given number is called cube root

Prime factorization method:

Prime factorization is a number written as the product of all its prime factors.

In order of finding cube root by prime factorization we use the following steps:

Step I : Obtain the given number

Step II : Resolve it into prime factors.

Step III : Group the factors in 3 in such a way that each number of the group is same

Step IV : Take one factor from each group

Step V : Find the product of the factors obtained in step IV. This product is the required cube root

Prime factorization of 175616:

\text{ prime factors of 175616 } = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7 prime factors of 175616 =2×2×2×2×2×2×2×2×2×7×7×7

Thus we get,

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 7}

3

175616

=

3

2×2×2×2×2×2×2×2×2×7×7×7

Make the groups of 3 of equal numbers

\sqrt[3]{175616} = \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{2 \times 2 \times 2 \times } \times \sqrt[3]{2 \times 2 \times 2} \times \sqrt[3]{7 \times 7 \times 7}

3

175616

=

3

2×2×2

×

3

2×2×2×

×

3

2×2×2

×

3

7×7×7

So there are 4 equal groups. So from that group take one factor out

\sqrt[3]{175616} = 2 \times 2 \times 2 \times 7 = 56

3

175616

=2×2×2×7=56

Thus Cube root of 175616 by prime factorization method is 56

please mark me as a brainlist

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3 years ago
5. – 3(1 + 6r) = 14 - 7​
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Answer:

r= -1.8

Step-by-step explanation:

Distribute

-3-18r=14-7

Combine like terms

-3-18r=7

add 3 to both sides

-18r=10

divide by -18

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3 years ago
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Answer:

t12= -8

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Sub into (3) into equ (2)

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Divide both sides by 7

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10=a+2(-2)

10=a-4

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a=14

t12=a+11d

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