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Pavel [41]
3 years ago
10

Please Help I need this done within the next 5 minutes

Mathematics
1 answer:
vazorg [7]3 years ago
7 0

Answer:

20 +(x+15.5)

Step-by-step explanation:

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svp [43]

Since we have the length and width of the window, we can multiply the two values.

Convert both fractions to improper fractions

(26/3)*(23/4)

=598/12 ft squared

= This simplifies to 49 5/6 ft. squared

7 0
3 years ago
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William buys two bags of peaches and three bags of apricots for $17. Sylvia buys four bags of peaches and two bags of apricots f
Rus_ich [418]

Answer: One bag of peaches : $22

Step-by-step explanation:

Hi, to answer this question we have to write an equation for William and Sylvia.

  • <em>William: 2 p + 3 a = 17 </em>
  • <em>Silvia: 4p + 2 a =22 </em>

Where:

p = price of one bag of peaches

a= price of one bag of apricots

Solving for "a" in William's equation:

2p +3a =17

3a = 17-2p

a = (17-2p)/3

a= 17/3 -2/3 p

Replacing "a" in Silvia's equation

4p + 2 a =22

4p + 2 (17/3 -2/3p) =22

4p +34/3-4/3p =22

4p-4/3p =22-34/3

8/3 p =32/3

p =32/3 ÷8/3

p=4

4 0
3 years ago
Twenty-five lamps are placed around a circle-shaped garden. How many straight lines could be found if each lamp is connected to
astraxan [27]

Answer:

300

Step-by-step explanation:

every lamp can connect other lamps ,from the first ,it can connect the other 24 lamps,and then, the second ,can also connect other 24 。but the line between the first and the second is counted twice。

so it would be:

(1+2+3+...+24)×24÷2=300

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3 years ago
Janelle and three of her friends bought four smoothies for a total of $3. If she purchases smoothies on another day for herself
bogdanovich [222]
Janelle will spend $7.50 because each smoothie costs .75 cents.
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3 years ago
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<img src="https://tex.z-dn.net/?f=%20%7C%20%7Bx%7D%5E%7B2%7D%20%2B%203x%20%2B2%20%7C%20%3C%202x%20%2B%204" id="TexFormula1" titl
Snezhnost [94]

\\ \tt\hookrightarrow |x^2+3x+2|

Either

\\ \tt\hookrightarrow x^2+3x+2

\\ \tt\hookrightarrow x^2+3x+2x

\\ \tt\hookrightarrow x^2+5x+6

\\ \tt\hookrightarrow (x+2)(x+3)

\\ \tt\hookrightarrow x

Or

\\ \tt\hookrightarrow x^2+3x+2

\\ \tt\hookrightarrow x^2+x-2

\\ \tt\hookrightarrow x^2+2x-x-2

\\ \tt\hookrightarrow (x+2)(x-1)

\\ \tt\hookrightarrow x

So

\\ \tt\hookrightarrow x\in (-3,1)

7 0
2 years ago
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