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Paladinen [302]
3 years ago
7

What is 2 and 1 3rd times 5​

Mathematics
2 answers:
DedPeter [7]3 years ago
5 0
2 1/3 = (mixed # x denominator) + numerator/ denominator

= 2x3+1/ 3= 7/3



7/3 x 5= 35/3= 11 2/3



scZoUnD [109]3 years ago
4 0

Answer:

2\frac{1}{3}x5=11\frac{2}{3}

Step-by-step explanation:

5x2=10

\frac{1}{3}x5=\frac{5}{3}

\frac{5}{3}=1\frac{2}{3}

10+1\frac{2}{3}=11\frac{2}{3}

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e

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Help please!! 15 points!!
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A and D

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One side-base right triangle and one angle-based right triangle.

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I need help on this question
Irina18 [472]

To find the surface area of the figure , we need to add the surface area of all the faces

So the surface area of figure = Area of two lateral rectangular faces + Area of two triangular faces + area of base

hence

Surface Area of figure = 2(10*15) + 2( 1/2 * 8 * 12) + (12*15)

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7 0
3 years ago
Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati
IrinaK [193]

Answer:

1. The minimum head breadth that will fit the clientele is of 3.95-in.

2. The maximum head breadth that will fit the clientele is of 9.25-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 6.6-in and a standard deviation of 1.1-in.

This means that \mu = 6.6, \sigma = 1.1

1. What is the minimum head breadth that will fit the clientele?

The 0.8th percentile, which is X when Z has a p-value of 0.008, so X when Z = -2.41.

Z = \frac{X - \mu}{\sigma}

-2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = -2.41*1.1

X = 3.95

The minimum head breadth that will fit the clientele is of 3.95-in.

2. What is the maximum head breadth that will fit the clientele?

The 100 - 0.8 = 99.2nd percentile, which is X when Z has a p-value of 0.992, so X when Z = 2.41.

Z = \frac{X - \mu}{\sigma}

2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = 2.41*1.1

X = 9.25

The maximum head breadth that will fit the clientele is of 9.25-in.

8 0
3 years ago
16 ÷ 22 + (6 x 2) - 8
stepladder [879]
I did the PEMDAS method (P= parentheses, E= exponents, M= multiplication, D = Division, A= addition, S = subtraction.)

First I did what’s inside the parentheses, (6x2) and got 12.

Then I divided 16 by 22 and received 0.72.

I added 0.72 with 12 and the result was 12.72.

Last step was to subtract 12.72 - 8 and that equals 4.72
3 0
3 years ago
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