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2 years ago

Help, please! This question may take some time to answer.

Mathematics

1 answer:

tatyana61 [14]2 years ago

7 0

Answer:

0.15-0.75p? YES

-0.45-0.6+0.75P? NO

-3(-0.05+0.25p)? YES

-3(0.15)+(-3)(0.2)+(-3)(0.25p)? NO

Step-by-step explanation:

-3(0.15-0.2+0.25p)

=-0.45+0.6-0.75p

=0.15-0.75p

1. 0.15-0.75p=0.15-0.75p? YES

2. -0.45-0.6+0.75P=0.15-0.75p?

-1.05+0.75p=0.15-0.75p? NO

3. -3(-0.05+0.25p)=0.15-0.75p?

0.15-0.75=0.15-0.75p? YES

4. -3(0.15)+(-3)(0.2)+(-3)(0.25p)=0.15-0.75p?

-0.45-0.6-0.75p=0.15-0.75p?

-1.05-0.75p=0.15-0.75p? NO

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Leslie determined that the system of equations below has infinitely many solutions. Is she correct?

Nookie1986 [14]

Answer:

Leslie determined that the system of equations below has infinitely many solutions. Is she correct?

x=4y-4

2x-8y=-24

A.Yes, Leslie is correct.

B. No, the solution is (-8,-24)

C. No, the solution is (0,-16)

D. No, the system of equations has no solution. 

Step-by-step explanation:

you have to solve they as a pair of simultaneous equations and their is no solutions

if you need a more detailed explanation post the question again and i will write a detailed explanation

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3 years ago

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Let f(x)=x^3-x-1

alexira [117]

$f(x) = x^3 - x - 1$

To find the gradient of the tangent, we must first differentiate the function.

$f'(x) = \frac{d}{dx}(x^3 - x - 1) = 3x^2 - 1$

The gradient at x = 0 is given by evaluating f'(0).

$f'(0) = 3(0)^2 - 1 = -1$

The derivative of the function at this point is negative, which tells us the function is decreasing at that point.

The tangent to the line is a straight line, so we will have a linear equation of the form y = mx + c. We know the gradient, m, is equal to -1, so

$y = -x + c$

Now we need to substitute a point on the tangent into this equation to find c. We know a point when x = 0 lies on here. To find the y-coordinate of this point we need to evaluate f(0).

$f(0) = (0)^3 - (0) - 1 = -1$

So the point (0, -1) lies on the tangent. Substituting into the tangent equation:

$y = -x + c \\\\ -1 = -(0) + c \\\\ -1 = c \\\\ \text{Equation of tangent is } \boxed{y = -x - 1}$

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3 years ago

Find the volume of the figure.

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Answer:

Step-by-step explanation:

1. Base x Height x Length

1 x 4 x 3= 12

8 0

2 years ago

NEED HELP FOR THIS QUESTION

const2013 [10]

Answer:

(a) A = 0.00278787878787878x

(b) B = 0.00235294117647058x + 3

For buying by credit card

For 700 BWP: Cost = A = £1.95

For 800 BWP: Cost = A = £2.23

For 800 BWP: Cost = A = £2.79

For buying from a Bureau de Change

The equation (4) is used as follows:

For 700 BWP: Cost = B = £4.65

For 800 BWP: Cost = B = $4.88

For 1000 BWP: Cost = B = £5.35

(d) You would have to buy 6,897.54 pulas for the cost to be the same whether you use a credit card or cash.

Step-by-step explanation:

(a) by credit card

For the exchange rate, we have:

8.25 BWP = £1 ⇒ 8.25 / 8.25 BWP = £1 / 8.25 = 1.00 BWP = £0.121212121212121

The expression can therefore be written as follows:

A = £0.121212121212121 * r * x ................. (1)

Where;

A = cost (including commission) of buying a particular number of Botswana pulas by credit card

r = commission on a credit card transaction = 2.3%, or 0.023

x = the number of pulas bought

Substituting for r into equation (1), we have:

A = £0.121212121212121 * 0.023 * x

A = 0.00278787878787878x ................. (2)

Equation (2) is the expression.

(b) from a Bureau de Change

For the exchange rate, we have

8.5 BWP = £1 ⇒ 8.5 / 8.5 BWP = £1 / 8.5 = 1.00 BWP = 0.117647058823529

B = (£0.117647058823529 * r * x) + F ................. (3)

Where;

B = cost (including commission) of buying a particular number of Botswana pulas by from a Bureau de Change.

r = commission charged by Bureau de Change. = 2%, or 0.02

x = the number of pulas bought

F = fee = £3

Substituting for r and F into equation (3), we have:

B = (£0.117647058823529 * 0.02 * x) + £3

B = 0.00235294117647058x + 3 ................. (4)

Equation (4) is the expression.

c. Evaluate each of these expressions for 700 BWP, 800 BWP, and 1000 BWP respectively.

For buying by credit card

The equation (2) is used as follows:

For 700 BWP: A = £0.00278787878787878 * 700 = £1.95

For 800 BWP: A = £0.00278787878787878 * 800 = £2.23

For 800 BWP: A = £0.00278787878787878 * 1000 = £2.79

For buying from a Bureau de Change

The equation (4) is used as follows:

For 700 BWP: B = (£0.00235294117647058 * 700) + £3 = £1.65 + £3 = £4.65

For 800 BWP: B = (£0.00235294117647058 * 800) + £3 = £1.88 + £3 = $4.88

For 1000 BWP: B = (£0.00235294117647058 * 1000) + £3 = £2.35 + £3 = £5.35

d. Hazard a guess as to the number of pulas you would have to buy for the cost to be the same whether you use a credit card or cash.

This can be calculated by equating equations (2) and (4) and then solve for x as follows:

0.00278787878787878x = 0.00235294117647058x + 3

0.00278787878787878x - 0.00235294117647058x = 3

x(0.00278787878787878 - 0.00235294117647058) = 3

x0.0004349376114082 = 3

x = 3 / 0.0004349376114082

x = 6,897.54 pulas

Therefore, you would have to buy 6,897.54 pulas for the cost to be the same whether you use a credit card or cash.

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3 years ago

Determine the value of x which satisfies the following equation. ln(4x+1)=6

Anika [276]

Answer:

Not Determinable

Step-by-step explanation:

Simplifying

Ln(4x + 1) = 6

Reorder the terms:

nL(1 + 4x) = 6

(1 * nL + 4x * nL) = 6

(1nL + 4nxL) = 6

Solving

1nL + 4nxL = 6

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Reorder the terms:

-6 + 1nL + 4nxL = 6 + -6

Combine like terms: 6 + -6 = 0

-6 + 1nL + 4nxL = 0

The solution to this equation could not be determined.

6 0

3 years ago

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