1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
meriva
3 years ago
7

A researcher surveyed five randomly selected employees from each of four different companies about their daily commutes to work.

the table shows the commute times for the surveyed employees.
Amount of time of company 1: 24, 26, 28, 23, 21
Amount of time for company 2: 6, 32, 9, 31, 21
Amount of time for company 3: 15, 15, 15, 15, 15
Amount of time for company 4: 13, 10, 45, 12, 15
 based on the data, which company most likely has the longest average commute time per employee?

(Please help me, i don't understand what they're trying to say)
Mathematics
2 answers:
Yuki888 [10]3 years ago
6 0
Its company 1. if you find the means of all of the company's, company 1 has the biggest mean which means they have the longest commute. So the answer is company 1
ANEK [815]3 years ago
5 0

Answer:

Company 1 most likely has the longest average commute time per employee.  

Step-by-step explanation:

A researcher surveyed five randomly selected employees from each of four different companies about their daily commutes to work.

We have to find which company most likely has the longest average commute time per employee.

So we will find the mean of the given each company's data

Mean = Sum of total number /total number of values

For Company 1 :  \frac{24 + 26 + 28 + 23 + 21 }{5} = 24.4

For company 2 : \frac{6+32+9+31+21}{5} = 19.8          

For company 3 :  \frac{15+15+15+15+15}{5} = 15                      

For company 4 : \frac{13+10+45+12+15}{5} = 19    

As we can see Company 1 has largest mean.

So Company 1 most likely has the longest average commute time per employee.  

You might be interested in
Which equation is equivalent to –k + 0.03 + 1.01k = –2.45 – 1.81k
Nat2105 [25]
-k + 0.03 + 1.01K = -2.45 - 1.81k
0.01k + 0.03 = -2.45 - 1.81k
0.01k + 1.81k = -2.45 - 0.03
1.82k = -2.48
8 0
3 years ago
4x + 3y = 5<br> 2x – y=5<br> Use substitution method
lukranit [14]

Answer:  Slope = -2.667/2.000 = -1.333

 x-intercept = 5/4 = 1.25000

 y-intercept = 5/3 = 1.66667

Step-by-step explanation: Slope is defined as the change in y divided by the change in x. We note that for x=0, the value of y is 1.667 and for x=2.000, the value of y is -1.000. So, for a change of 2.000 in x (The change in x is sometimes referred to as "RUN") we get a change of -1.000 - 1.667 = -2.667 in y. (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)

7 0
3 years ago
Solve the system of equations below
DENIUS [597]

Answer:

The answer is B. (-7,-2)

Step-by-step explanation:

Multiply the first equation by 7,and multiply the second equation by -6.

7(−3x+6y=9)

−6(5x+7y=−49)

Becomes:

−21x+42y=63

−30x−42y=294

Add these equations to eliminate y:

−51x=357

Then solve−51x=357for x:

−51x=357 Divide both sides by -51

x=-7

Write down an original equation:

−3x+6y=9

Substitute−7forxin−3x+6y=9:

(−3)(−7)+6y=9

6y+21=9(Simplify both sides of the equation)

6y+21+−21=9+−21(Add -21 to both sides)

6y=−12

y=-2

4 0
3 years ago
For two events A and B show that P (A∩B) ≥ P (A)+P (B)−1.
nordsb [41]

Answer:

<h3>For two events A and B show that P (A∩B) ≥ P (A)+P (B)−1.</h3>

By De morgan's law

(A\cap B)^{c}=A^{c}\cup B^{c}\\\\P((A\cap B)^{c})=P(A^{c}\cup B^{c})\leq P(A^{c})+P(B^{c}) \\\\1-P(A\cap B)\leq  P(A^{c})+P(B^{c}) \\\\1-P(A\cap B)\leq  1-P(A)+1-P(B)\\\\-P(A\cap B)\leq  1-P(A)-P(B)\\\\P(A\cap B)\geq P(A)+P(B)-1

which is Bonferroni’s inequality

<h3>Result 1: P (Ac) = 1 − P(A)</h3>

Proof

If S is universal set then

A\cup A^{c}=S\\\\P(A\cup A^{c})=P(S)\\\\P(A)+P(A^{c})=1\\\\P(A^{c})=1-P(A)

<h3>Result 2 : For any two events A and B, P (A∪B) = P (A)+P (B)−P (A∩B) and P(A) ≥ P(B)</h3>

Proof:

If S is a universal set then:

A\cup(B\cap A^{c})=(A\cup B) \cap (A\cup A^{c})\\=(A\cup B) \cap S\\A\cup(B\cap A^{c})=(A\cup B)

Which show A∪B can be expressed as union of two disjoint sets.

If A and (B∩Ac) are two disjoint sets then

P(A\cup B) =P(A) + P(B\cap A^{c})---(1)\\

B can be  expressed as:

B=B\cap(A\cup A^{c})\\

If B is intersection of two disjoint sets then

P(B)=P(B\cap(A)+P(B\cup A^{c})\\P(B\cup A^{c}=P(B)-P(B\cap A)

Then (1) becomes

P(A\cup B) =P(A) +P(B)-P(A\cap B)\\

<h3>Result 3: For any two events A and B, P(A) = P(A ∩ B) + P (A ∩ Bc)</h3>

Proof:

If A and B are two disjoint sets then

A=A\cap(B\cup B^{c})\\A=(A\cap B) \cup (A\cap B^{c})\\P(A)=P(A\cap B) + P(A\cap B^{c})\\

<h3>Result 4: If B ⊂ A, then A∩B = B. Therefore P (A)−P (B) = P (A ∩ Bc) </h3>

Proof:

If B is subset of A then all elements of B lie in A so A ∩ B =B

A =(A \cap B)\cup (A\cap B^{c}) = B \cup ( A\cap B^{c})

where A and A ∩ Bc  are disjoint.

P(A)=P(B\cup ( A\cap B^{c}))\\\\P(A)=P(B)+P( A\cap B^{c})

From axiom P(E)≥0

P( A\cap B^{c})\geq 0\\\\P(A)-P(B)=P( A\cap B^{c})\\P(A)=P(B)+P(A\cap B^{c})\geq P(B)

Therefore,

P(A)≥P(B)

8 0
3 years ago
Simplify the ratio 11/33 and then give 2 more equivalent ratios
KATRIN_1 [288]
The simplest ratio is 1/3. Equivalent ratios would be 3/9 and 5/15.
4 0
3 years ago
Other questions:
  • What is the value of d if the volume of Prism F is 99 cubic units ?
    7·1 answer
  • If f(x) = 5x^3-2 and g(x)= 2x+1, find (f+g) (x).
    9·2 answers
  • What is the number of solid 3-inch by 2-inch by 2-inch rectangular prisms that can be
    7·1 answer
  • Lance wants to find the total length of 3 boards.He uses the expression 3 1/2+( 2+4 1/2 how can lance rewrite the expression usi
    9·2 answers
  • A certain shade of pink is created by adding 3 cups of red paint to 7 cups of white paint.
    14·1 answer
  • Ii s possible to help me pls!
    6·1 answer
  • Which of x- values are solutions to the following inequality?​
    12·1 answer
  • REWARDING 100+ POINTS IF ONE PERSON GETS THIS CHALLENGING PROBLEM RIGHT
    15·1 answer
  • Two groups of tourists are on the same floor of a skyscraper they are visiting, and they board adjacent elevators at the same ti
    5·1 answer
  • ​ 5\left(x+20\right)=5(x+20)= 7x+307x+30
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!