I think for the question above, instead of 2 · 3^2 · 7 it is <span>2 · 3^2 · 5.
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Two numbers have prime factorizations of 2^2 • 3 • 5 and 2 • 3^2 • 5 (note 2 squared & 3 squared).
Now, to choose the GCF, you choose, for each base factor in either number, the least exponent-ed one; so the GCF needs a factor 2, a factor 3, and a factor 5. Thus the GCF is 30 (their product). [i.e,2 squared is not a common factor]
<span>To create the LCM, you choose, for each base factor in either number, the greatest exponented one. Thus, LCM needs a factor 2 squared, 3 squared, and 5, giving LCM = 4(9)(5) = 180.</span><span />
Answer:
radius is 8cm
Step-by-step explanation: radius is half of diameter so 16/2= 8
Answer:
i tihnk it would be just -3
Step-by-step explanation:
Answer:
Step-by-step explanation:
prime factorization
40y³ = 2³×5y³
625 = 5⁴
Greatest common factor = 5
40y³ - 625 = 5(8y³ - 125)
Note that 8y³ - 125 is the difference of cubes.
8y³ - 125 = (2y)³ - 5³ = (2y-5)((2y)² + 2y·5 + 5²) = (2y-5)(4y² + 10y + 25)
40y³ - 625 = 5(2y-5)(4y² + 10y + 25)
Answer:
Step-by-step explanation:
Given that X and Y are independent random variables with the following distributions:
x -1 10 1 2 Total
p 0.3 0.1 0.5 0.1 1
xp -0.3 1 0.5 0.2 1.4
x^2p 0.3 10 0.5 0.4 11.2
Mean of X = 1.4
Var(x) = 11.2-1.4^2 = 9.24
y 2 3 5
p 0.6 0.3 0.1 1
yp 1.2 0.9 0.5 0 2.6
y^2p 2.4 2.7 2.5 0 7.6
Mean of Y = 2.6
Var(Y) = 11.2-1.4^2 = 0.84
3) W=3+2x
Mean of w =3+2*Mean of x = 7.2
Var (w) = 0+2^2 Var(x)= 36.96
