All categories

2 years ago

Can someone show me how to solve this equation:

Mathematics

1 answer:

miskamm [114]2 years ago

4 0

-6(4x + 3) = 6(-4x - 3)
-6(4x) - 6(3) = 6(-4x) - 6(3)
-24x - 18 = -24x - 18
+ 24x + 24x
-18 = -18

It is infinite.

You might be interested in

What shape is a rhombus related to and why

Ksju [112]

A rhombus is related to a “Parallelogram”

Why? - because it fulfills the requirements of a parallelogram: a quadrilateral with two pairs of parallel sides. It goes above and beyond that to also have four equal-length sides, but it is still a type of parallelogram.

hope this helped <3

8 0

2 years ago

Use synthetic division to find the remainder. When 3x^ 2 - 2x - 4 is divided by x - 3.

OlgaM077 [116]

ANSWER

a.)17

EXPLANATION

The given function is

$3 {x}^{2} - 2x - 4$

We want to find the remainnder when this function is divided by x-3 using synthetic division.

We write the coefficients of the given function and carry out the synthetic division as shown in the attachment.

The remainnder is 17.

The correct answer is A.

7 0

3 years ago

Estimate numbers 1-4 from the tens place value. 1. 89 2. 64 3. 985 4. 467

zhenek [66]

$\huge\text{Hey there!}$

$\huge\text{We are not sure what you want us to}\\\huge\text{round to so I will...}\huge\boxed{\downarrow}\\\\\\\huge\boxed{\mathsf{original \ number\rightarrow tens\rightarrow hundreds/thousands}}$

$\huge\boxed{1.) \ \mathsf{89} \rightarrow \bold{90}\rightarrow\bf 100}}\\\huge\boxed{2.) \mathsf{\ 64\rightarrow \bold{6} \rightarrow \bf 100}}\\\huge\boxed{3.) \mathsf{ \ 985 \rightarrow \bold{990}\rightarrow \bf 1,000}}\\\huge\boxed{4.)\mathsf{\ 467\rightarrow\bold{470}\rightarrow \bf 500}}}$

$\huge\textsf{Reminder: If you have \bf 0 - 4 you are going}\\\huge\textsf{\bf downward \& 5 - 9 you are going upward}$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\huge\boxed{\frak{Amphitrite1040:)}}$

5 0

3 years ago

whats 10+1000-2+2600+9000+2= im in 7th grade im doing thia cheap question to give brainliest out and freinds so if want brainlie

frosja888 [35]

Answer:

12610

Step-by-step explanation:

7 0

3 years ago

If the Math Olympiad Club consists of 11 students, how many different teams of 3 students can be formed for competitions?

vivado [14]

Answer:

165 different teams of 3 students can be formed for competitions

Step-by-step explanation:

Combinations of m elements taken from n in n (m≥n) are called all possible groupings that can be made with the m elements so that:

Not all items fit
No matter the order
Elements are not repeated

That is, a combination is an arrangement of elements where the place or position they occupy within the arrangement does not matter. In a combination it is interesting to form groups and their content.

To calculate the number of combinations, the following expression is applied:

$C=\frac{m!}{n!*(m-n)!}$

It indicates the combinations of m objects taken from among n objects, where the term "n!" is called "factorial of n" and is the multiplication of all the numbers that go from "n" to 1.

In this case:

n: 3
m: 11

Replacing:

$C=\frac{11!}{3!*(11-3)!}$

Solving:

$C=\frac{11!}{3!*8!}$

being:

3!=3*2*1=6
8!=8*7*6*5*4*3*2*1=40,320
11!=39,916,800

So:

$C=\frac{39,916,800}{6*40,320}$

C= 165

165 different teams of 3 students can be formed for competitions

3 0

2 years ago