The distance from the speaker would the sound be barely audible is 477.46km.
<h3>
What is distance?</h3>
It's how far away two objects or locations are measured numerically as distance. Distance in physics or common language can refer to a physical length or an assumption based on other factors (e.g. "two counties over"). Sometimes the symbol |AB| is used to indicate how far apart two points are. "Distance from A to B" and "Distance from B to A" are typically equivalent terms. A distance function or metric in mathematics is an extension of the idea of physical distance; it defines what it means for components in a space to be "near to" or "far away" from one another. Distance is a non-numerical unit of measurement in the social sciences and psychology.
Explanation:
Sound audible(barely) = 0dB
I= 10.709*I/
=0
I= 
*
=w/
![distance(r)=\sqrt[]{\frac{P}{4\pi I} } =\sqrt[]{\frac{6}{4\pi * 10^{-12} } } =477.46 km](https://tex.z-dn.net/?f=distance%28r%29%3D%5Csqrt%5B%5D%7B%5Cfrac%7BP%7D%7B4%5Cpi%20I%7D%20%7D%20%3D%5Csqrt%5B%5D%7B%5Cfrac%7B6%7D%7B4%5Cpi%20%2A%2010%5E%7B-12%7D%20%7D%20%7D%20%3D477.46%20km)
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Answer:
Ep = 3797.05 N/C in the direction leaving the charge q₂ towards point P
Explanation:
Conceptual analysis
The electric field at a point P due to a point charge is calculated as follows:
E = k*q/d²
E: Electric field in N/C
q: charge in Newtons (N)
k: electric constant in N*m²/C²
d: distance from charge q to point P in meters (m)
Data
k= 8.99*10⁹ N*m²/C²
q₁ = +13.6 x 10⁻⁹C
q₂ = +61.0*10⁻⁹C
d₁ =d₂= 33.5 cm = 0.335 m
Look at the attached graphic:
E₁: Electric Field at point P due to charge q₁. As the charge q₁ is positive (q₁+) ,the field leaves the charge
E₂: Electric Field at point P due to charge q₂. As the charge q₂ is positive (q₂+) ,the field leaves the charge
E₁ = k*q₁/d₁² = 8.99*10⁹ *13.6 *10⁻⁹/(0.335)² = 1089.45 N/C
E₂ = k*q₂/d₂²=- 8.99*10⁹ *61*10⁻⁹/(0.335)² = - 4886.5 N/C
Magnitude of the electric field at a point midway between q₁ and q₂
Ep= - 4886.5+ 1089.45 = -3797.05 N/C
Ep = 3797.5 N/C in the direction leaving the charge q₂ towards point P
Use a ruler, a pivot, some weights. set the experiment by putting the pivot then a ruler on top of it finally put the wights on each end of the ruler
1 is idk
2 is solvent
3 is gamma rays
4 is transmutation
5 is nuclear fission
6 is nuclear fusion
7 is tracer
8 is half life
9 is
10 is strong force
11 is radioactivity
12 is dissociation
13 is unsaturated solution
14 idk
16 is alpha particle
17 is radioactivity
18 is concentration
19 is solubility
20 is saturated solution
21 is dissociation
22 is saturated solution
23 is saturated solution
24 is idk
25 is electrolytes
26 is idk
27 is non electrolytes
28 is concentration
29 is dissociation
30 is idk
Answer:
Person in the Control group: SpongeBob
Independent variable: Muscle cream
Dependent variable: Amount of muscle power
Larry's conclusion should conclude that the MUSCLE CREAM double a person’s muscle power when used as part of a muscle-building workout.
Explanation:
Independent variable is the variable that is changed or manipulated by the experimenter in an experiment. In this experiment, the MUSCLE CREAM is the variable being changed for the groups i.e. Patrick and SpongeBob. Hence, the MUSCLE CREAM is the independent variable.
The dependent variable is the variable that responds to changes made to the independent variable. In this experiment, the dependent/responding variable is the AMOUNT OF MUSCLE POWER.
Control group is the group of an experiment that does not receive the experimental variable (muscle cream). In this experiment, the person that does not receive the experimental variable is SpongeBob i.e. was lathered with the regular lotion.
Larry, who is the one conducting the experiment, should conclude that MUSCLE POWER doubles a person’s muscle power when used as part of a muscle-building workout.
