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AysviL [449]
3 years ago
10

According to Kepler's Third Law, a solar-system planet that has an orbital radius of 4 AU would have an orbital period of about

_________ year(s).
Physics
1 answer:
NARA [144]3 years ago
6 0

Answer:

Orbital period, T = 1.00074 years

Explanation:

It is given that,

Orbital radius of a solar system planet, r=4\ AU=1.496\times 10^{11}\ m

The orbital period of the planet can be calculated using third law of Kepler's. It is as follows :

T^2=\dfrac{4\pi^2}{GM}r^3

M is the mass of the sun

T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times (1.496\times 10^{11})^3    

T^2=\sqrt{9.96\times 10^{14}}\ s

T = 31559467.6761 s

T = 1.00074 years

So, a solar-system planet that has an orbital radius of 4 AU would have an orbital period of about 1.00074 years.

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2 years ago
What is the speed of a bobsled whose distance-time graph indicates that it traveled 119m in 27s
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3 years ago
A jet airliner moving initially at 406 mph (with respect to the ground) to the east moves into a region where the wind is blowin
astraxan [27]

Answer:

966 mph

Explanation:

Using as convention:

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The x- and y- components of the initial velocity of the jet can be written as

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3 years ago
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