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denpristay [2]
3 years ago
8

can somebody help with this? i have less than an hour to do it lol .. it has to do with z-scores 40pts

Mathematics
1 answer:
kakasveta [241]3 years ago
7 0

Answer:

i think it is 7/8 but i'm not sure

Step-by-step explanation:

You might be interested in
What is the length of side AD?. . . 6 cm. 8.5 cm. 10.4 cm. 12 cm
ludmilkaskok [199]
In triangle ABC, AC = 12/ (sin30) = 12 / (1/2) = 24
DC = 24-x
DB = DC tan 30 = (24-x)  tan30 <span>=(24−x)/</span><span>√3
</span>

In triangle ADB using Pythagorean Theorem<span><span>x2</span>+((24−x)/<span>√3</span><span>)2</span>=<span>12^2</span></span><span><span>x2</span>+(24−x<span>)^2</span>/3=<span>12^2</span></span><span>3<span>x2</span>+(24−x<span>)^2</span>=432</span><span>4<span>x2</span>−48x+576=432</span><span>4<span>x2</span>−48x+144=0</span><span><span><span>x2</span>−12x+36=0
x1 = x2 =6

AD = AC - DC = 24- (24-x) = 6</span></span>
5 0
3 years ago
Read 2 more answers
Could someone help me please ​
Alexxx [7]

1. 3x+9-9=18-9      

3x=9

x=3

2. 4x-12=20

4x-12+12=20+12

4x=32

x=8

3. x+0-0

x=0

4. x/2-2+2=9+2

x/2=11

(2)(x/2)=11(2)

x=22

5. 12x-21=3

12x-21+21=3+21

12x=24

x=2

6. 3x-15=18

3x-15+15=18+15

3x=33

x=11

7. 3x-25=14

3x-25+25=14+25

x=13

8. 3x+16=22

3x+16-16=22-16

x=2

9. 2x-8=2

2x-8+8=2+8

2x=10

x=5

10. 9x-18=9

9x-18+18=9+18

9x=27

x=3

11. x+0=0

x=0

12. 9x-8=19

9x-8+8=19+8

9x=27

x=3

If  you want to check my answers

use substitution method by using the x into for each equation.

7 0
3 years ago
Read 2 more answers
Farmer Bill sold potatoes at the farm market. He sold a quarter to the first person, 4/9 of what was left to the second person,
mel-nik [20]

Answer: 120 lb of potatoes.

Step-by-step explanation:

Let the pounds of potatoes sold by farmer Bill      = X lb

Fractional part sold to the first person                    = 1/4

Therefore 1/4 of X                                                      = 1/4  x X

                                                                                    = X/4 lb of potatoes.

No of potatoes left for sale                                        = X - X/4

                                                                                    = ( 4x - x )/4

                                                                                    = 3x/4 lb.

Fractional part sold to the second person out of the reminder = 4/9

Therefore 4/9 of 3x/4                                                 = 4/9 x 3x/4

                                                                                    = x/3 lb of potatoes.

Amount of potatoes left for sale                               = 3x/4 - x/3

Resolve into fraction , we have                                 = (9x - 4x)/12, because 12 is the LCM.

                                                                                    = 5x/12

Third buyer bought 4/5 of the left over                    = 4/5 of 5x/12

                                                                                   =   x/3 lb of potatoes.

Amount  of potatoes left                                           =   5x/12 - x/3

Resolve in to fraction again  taking 12 as the LCM =   ( 5x - 4x )/12

                                                                                   = x/12 lb of potatoes .

Therefore, the left over was 10 lb .

To determine the value of x now which correspond to the amount of potatoes sold by Farmer Bill, we shall the equate the left to  x/12 = 10                                                                                                                

we now cross multiply to get the value of x                             x = 120 lb.

therefore the pound of potatoes sold by farmer Bill  = 120 lb.                                        

                                                                                 

4 0
3 years ago
A​ town's population increases in one year from 50,000 to 58,000. If the population is growing​ linearly, at a steady​ rate, the
jolli1 [7]

Answer:

66,000

Step-by-step explanation:

If a relation is linear, then for equal changes in x there are equal changes in y. If in 1 year the population increases by 8,000, then in any 1-year period, the population will also increase 8,000. The population started at 50,000. In 1 year, it became 50,000 + 8,000 = 58,000. At the end of the second year, it will have increased by another 8,000. 58,000 + 8,000 = 66,000.

4 0
3 years ago
The isosceles triangle below has height AQ of length 3 and base BC of length 2. A point P may be placed anywhere along the line
eduard

The question is missing parts. Here is the complete question.

The isosceles triangle below has height AQ of length 3 and base BC of length 2. A point P may be placed anywhere along the line segment AQ.

What is the minimum value of the sum of the lengths of AP, BP and CP?

Answer: The sum is 4.73.

Step-by-step explanation: <u>Height</u> of a triangle is a perpendicualr line linking a vertex and its opposite side.

Because triangle ABC is isosceles, point Q divides the base in 2 equal parts:

BQ = CQ = 1

Suppose QP = x

To calculate minimum value of the sum:

AP = AQ - QP

AP = 3 - x

Since triangles BQP and CQP are congruent and right triangles, use Pythagorean Theorem to figure out the value of BP and CP:

BP = CP = \sqrt{BQ^{2}+PQ^{2}}

BP = \sqrt{1+x^{2}}

Then, sum of AP, BP and CP is

f(x)=3-x+2\sqrt{1+x^{2}}

The minimum value is calculated using first derivative:

f'=-1+\frac{2x}{\sqrt{x^{2}+1} }

The value of x is limited: it can assume value of 0, when P=A and x=3, when P=Q. So, interval is [0,3].

x has value:

-1+\frac{2x}{\sqrt{x^{2}+1} }=0

2x=\sqrt{x^{2}+1}

4x^{2}-x^{2}-1=0

3x^{2}=1

x = ± \frac{1}{\sqrt{3} }

x can't assume negative value because is not in the interval:

x = \frac{1}{\sqrt{3} }

To find the minimum value of the sum, substitute x in the function above:

f(\frac{1}{\sqrt{3} })=3-\frac{1}{\sqrt{3} } +2\sqrt{1+(\frac{1}{\sqrt{3} })^{2} }

f(\frac{1}{\sqrt{3}} )=3-\frac{1}{\sqrt{3}}+2(\sqrt{\frac{4}{3} }  )

f(\frac{1}{\sqrt{3}} )=3-\frac{1}{\sqrt{3}} +\frac{4}{\sqrt{3}}

f(\frac{1}{\sqrt{3}} )=3+\frac{3}{\sqrt{3} }

f(\frac{1}{\sqrt{3}} )=4.73

<u>The </u><u>minimum value</u><u> of the sum of AP, BP and CP is </u><u>4.73.</u>

7 0
3 years ago
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