What is the slope of a line that is perpendicular to 6x + 3y = –9?

2 answers:

4 0

6x + 3y = -9
3y = -6x - 9
y = -2x - 4.5

slope (m1) of this line is -2

slope of the perpendicular line,
m2 = - (1/m1)
m2 = - (1 / -2)
m2 = 1/2

nekit [7.7K]3 years ago

3 0

6 x + 3 y = -9
3 y = - 6 x - 9 / : 3 ( divide both sides by 3 )
y = - 2 x - 3
m 1 = -2
Slope of the perpendicular line:
m 2 = - 1 / ( - 2 )
m 2 = 0.5

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andrew11 [14]

Hello!

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3 years ago

Given g(x) = −3x + 4

Goshia [24]

Answer:

The average rate of change of g from x = a to x = a + h is -3.

Step-by-step explanation:

We are given the function:

$g(x) = -3x + 4$

And we want to determine its average rate of change of the function for x = a and x = a + h.

To determine the average rate of change, we find the slope of the function between the two points. In other words:

$\displaystyle \text{Avg} = \frac{g(a + h) - g(a) }{(a + h ) - a}$

Simplify:

$\displaystyle \begin{aligned} \text{Avg} &= \frac{g(a + h) - g(a) }{(a + h ) - a} \\ \\ &=\frac{(-3(a+h) + 4) - (-3a+4)}{h} \\ \\ &= \frac{(-3a -3h + 4) + (3a - 4) }{h} \\ \\ &= \frac{-3h}{h} \\ \\ &= -3\end{aligned}$