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3 years ago

Can someone please help me Solve for y. Show your work 1. y - 3x < 5

Mathematics

1 answer:

Maurinko [17]3 years ago

4 0

Answer

Y<5+3x

Step-by-step explanation:

you add 3x to both side of 5 and it will end up being 5+3x

then y will be left then your done

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State p, as the subject of formula <img src="https://tex.z-dn.net/?f=q%20%3D%20%20%5Csqrt%7Bp%7D%20" id="TexFormula1" title=

Sladkaya [172]

Square both side as shown above

8 0

3 years ago

The University of Central Florida’s cheerleading team has eighteen males and twenty-one females. If h represents the height of a

morpeh [17]

Answer:

The range of heights of the cheerleaders is the interval [58, 74)

All real numbers greater than or equal to 58 inches and less than 74 inches

Step-by-step explanation:

we have

$260 \leq 4h+28$

Divide the compound inequality into two inequalities

$260 \leq 4h+28$ -----> inequality A

$4h+28$ -----> inequality B

Solve inequality A

$260 \leq 4h+28$

Subtract 28 both sides

$232 \leq 4h$

Divide by 4 both sides

$58 \leq h$

Rewrite

$h \geq 58\ in$

Solve the inequality B

$4h+28$

Subtract 28 both sides

$4h$

Divide by 4 both sides

$h$

therefore

The range of heights of the cheerleaders is the interval [58, 74)

All real numbers greater than or equal to 58 inches and less than 74 inches

3 0

3 years ago

The graph shown is a translation of the graph of f(x)=x^2. Write the function in vertex form.

Gnesinka [82]

$\sf \longrightarrow \: f(x) = {x}^{2}$

Write the parent function in the standard form I.e.

$\boxed{ \tt \:y =a(x - h) \times 2 + k }$

Where,

a = 1
h = 0
k = 0

$\sf \longrightarrow \:y= 1(x - 0)^{2} \times 2 + 0$

$\sf \longrightarrow \: y = (x - 0) ^{2} \times 2 + 0$

$\sf \longrightarrow \: y = {x}^{2} \times 2$

$\sf \longrightarrow \: y = 2{x}^{2}$

4 0

3 years ago

H(x) = square root of x-10

Tju [1.3M]

Answer:

Step-by-step explanation:

8 0

3 years ago

What does 4/7x35= plz tell me

horrorfan [7]

Basically divide by 7 times 4
35/7= 5
5 times 4= 20

5 0

3 years ago

Read 2 more answers