All categories

3 years ago

Jamison turns around 5 times

Physics

2 answers:

Ghella [55]3 years ago

8 0

Answer:

UMMMMMMMMMMMMMMM ]

Explanation:

WHAT

forsale [732]3 years ago

7 0

Answer:

dang, he should go see a doctor

You might be interested in

A 0.8 m length of wire is formed into a single turn, square loop in which there is a current of 12 A. The loop is placed in magn

rewona [7]

Answer:

0.073 N-m

Explanation:

i = 12 A, l = 0.8 m, B = 0.12 T

The circumference of the loop is 0.8 m.

Let r be the radius of the loop.

2 x 3.14 x r = 0.8

r = 0.127 m

Maximum Torque = i x A x B

Maximum Torque = 12 x 3.14 x 0.127 x 0.127 x 0.12 = 0.073 N-m

8 0

4 years ago

How can you say that light is a form of energy?

Ierofanga [76]

Answer:

kinetic energy

Explanation:

Light is actually a form of kinetic energy that is visible to the human eye.

6 0

2 years ago

An object is moving forward and then gets knocked sideways, what is this force called?

Luda [366]

Answer:

It is called force.

Explanation:

A push or pull exerted on an object. Measured in Newtons. Friction & gravity are forces. There are balanced and unbalanced forces.

5 0

3 years ago

The reason a charged balloon will stick to a wall is that?

kari74 [83]

The negative charges of the balloon will stick to the positive charges on the wall.

6 0

3 years ago

A goalie kicks a soccer ball straight vertically into the air. It takes 5.00 s for the ball to reach its maximum height and come

Yuliya22 [10]

Answer:

(a) vo = 24.98m/s

(b) t = 5.09 s

Explanation:

(a) In order to calculate the the initial speed of the ball, you use the following formula:

$y=y_o+v_ot-\frac{1}{2}gt^2$ (1)

y: vertical position of the ball = 2.44m

yo: initial vertical position = 0m

vo: initial speed of the ball = ?

g: gravitational acceleration = 9.8m/s²

t: time on which the ball is at 2.44m above the ground = 5.00s

You solve the equation (1) for vo and replace the values of the other parameters:

$v_o=\frac{y-y_o+1/2gt^2}{t}$

$v_o=\frac{2.44m-0.00m+1/2(9.8m/s^2)(5.00s)^2}{5.00s}\\\\v_o=24.98\frac{m}{s}$

The initial speed of the ball is 24.98m/s

(b) To find the time the ball takes to arrive to the ground you use the equation (1) for y = 0m (ground) and solve for t:

$0=24.98t-\frac{1}{2}(9.8)t^2\\\\t=5.09s$

The time that the ball takes to arrive to the ground is 5.09s

5 0

3 years ago