Matter moves in the same direction in a longitudinal wave, and at right angles to the direction of a transverse wave.
Answer:
You will have to move 12.2 ft to decrease the initial intensity to 17 mRem/h.
Explanation:
The distance can be calculated using the following equation:
<u>Where</u>:
I₁ = 158 mRem/h
I₂ = 17 mRem/h
D₁ = 4 ft.
D₂=?
Hence, the distance D₂ is:
Therefore, you will have to move 12.2 ft to decrease the initial intensity to 17 mRem/h.
I hope it helps you!
Answer:
2.5 cm
Explanation:
Using the relation :
Refractive index = Real Depth / Apparent depth
Refractive index = 1.6
Real depth = 4cm
Virtual depth = apparent depth = x
1.6 = 4cm / x
1.6x = 4
x = 4 / 1.6
x = 2.5
Hence, virtual depth = 2.5cm
Answer:
The height from which the egg is dropped is <u>68.54 m</u>.
Explanation:
Given:
Initial velocity of egg is, (Dropped means initial velocity is 0)
Time taken is,
Acceleration experienced by egg is due to gravity,
The height from which the egg is dropped is,
Now, we use Newton's equation of motion that relates the distance, initial velocity, time and acceleration.
So, we have the following equation of motion:
Plug in all the given values and solve for 'd'. This gives,
Therefore, the height from which the egg is dropped is 68.54 m.