The miracle year for Albert Einstein was the year 1905 within which he published so many renowned papers.
<h3>When was Einstein miracle year?</h3>
The miracle year for Albert Einstein was the year 1905 within which he published so many renowned papers in a short time and became very popular.
His mindset in that year was one that challenged the orthodox explanations and sought to think outside the box.
Learn more about Albert Einstein:brainly.com/question/2964376
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No, energy transformation is occurring in every point of the motion.
In fact, the ball starts from point 1 with maximum kinetic energy and zero potential energy (taking the hand of the boy as reference level). The kinetic energy converts into gravitational potential energy as it goes higher: in point 2, part of the kinetic energy has converted into potential energy (because the velocity has decreased, while the height has increased), and then when the ball reaches point 3 all the kinetic energy has converted into potential energy (because now the velocity is zero, while the height is maximum). As the ball descends (point 4), the velocity starts to increase again, therefore the kinetic energy increases and the potential energy decreases (because the height is deacreasing now).
Summarizing, energy transformation is occuring in every point of the motion.
A <u>Food web</u> is multiple overlapping food chains.
Answer:
a) Δp = - 10113.2 Kg m / s, b) he rate of change is negative, c) F = 140.46N
Explanation:
a) For this part let's analyze a water particle, it has a velocity of 66 m / s and when it collides with the building its velocity changes to zero, so the change in moment is
Δp = mv_f - m v₀
Δp = -m v₀ (1)
the change of the moment in a second is
if 2429 gallons arrive in in minute (60s) in a second how many gallons arrive
c_agua = 2429/60
c_water = 40,483 gallon/ s
let's use the concept of density to find the mass
ρ = m / V
m = ρ V
let's reduce gallons to liters
c_water = 40,483 gal (3,785 l / 1 gal) = 153.23 l
m = 1 153.23
m 153.23 kg
we substitute in 1
Δp = - 153.23 66
Δp = - 10113.2 Kg m / s
b) From the previous result the rate of change is negative
c) Let's use the impulse ratio
I = f t = Δp
F t = Δp
F = Δp / t
F = 
F = 140.46 N
