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melamori03 [73]
3 years ago
8

7x - 4y = -20 solve for y

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
6 0

Answer:

y=5/4-7x/4

Step-by-step explanation:

PIT_PIT [208]3 years ago
6 0

Answer:

so your anwser would be Y = \frac{7x}{4} + 5

Step-by-step explanation:

y = 5 + \frac{7x}{4}

Reorder  5  and  \frac{7x}{4}

Y = \frac{7x}{4} + 5

after this step nothing else can be done

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vladimir2022 [97]
Letter D is the correct answer
3 0
3 years ago
Use the formula to determine the area of squares with side lengths of 3 cm, 10.5 cm, and π cm.
Nataliya [291]

Answer:

For length of side = 3 cm

Area of the square = 9 cm²

For length of side = 10.5 cm

Area of the square =  110.25 cm²

For length of side = π cm

Area of the square = 9.869 cm²

Step-by-step explanation:

The area of a square is given as :

Area = Side²

therefore,

For length of side = 3 cm

Area of the square = ( 3 cm )² = ( 3 × 3 ) cm² = 9 cm²

For length of side = 10.5 cm

Area of the square = ( 10.5 cm )² = ( 10.5 × 10.5 ) cm² = 110.25 cm²

For length of side = π cm

Area of the square = ( π cm )²  

= ( π × π ) cm²                

= 3.14² cm²                                [π = 3.14]

= 9.869 cm²

8 0
3 years ago
I need help on adding fraction in it simplest form?
Llana [10]
It is 6/9. 3 times 3 equals 9, so u have to multiply 2 times 3 and u get six.
2/3=6/9
8 0
3 years ago
Show work please I need help asap
rosijanka [135]

Answer:

12. -11

13. 2

Step-by-step explanation:

12. First recall the order of operations (BEDMAS): Brackets, Exponents, Division, Multiplication, Addition, Subtraction

For question 12 there is a division and its priority is before other operations in the equation so you must divide 16/-2 first which gives you -8.

From there because addition and subtraction is on the same level of order, you would do the question straight as it is shown (but replace 16/-2 with -8.

Your new equation is -10-8+7 = -11

13. follow the same as above using BEDMAS. It may help to look at it with additional brackets: ((-68)/(-4)) + ((5 x (-3))

  • keep in mind there’s an addition between the two

Division and multiplication is on the same level in BEDMAS so first divide -68/-4 = 17

Second multiply 5 x -3 = -15

Now you can combine the two answers using addition: 17 + (-15) = 2

5 0
3 years ago
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
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