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Zigmanuir [339]
3 years ago
10

Find the slope of the line. 1. (5, 3) (-5, 1)

Mathematics
1 answer:
Blizzard [7]3 years ago
8 0

Answer:

1/5

Step-by-step explanation:

y1-y2/x1-y2 = (3-1)/5-(-5)

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What’s the answer to this?
jasenka [17]

Answer:

It would be the first option: Last week, Rosemary walked at a faster pace.

Step-by-step explanation:

Last week, the speed was d=3h, as for this week, her speed was d=2.5h.

No one knows how many hours she walked this week so we cannot say that she walked a greater distance.

7 0
3 years ago
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Find each percent decrease. Round to the nearest percent.
Vsevolod [243]

Answer:

67%

Step-by-step explanation:

First of all, we must find the decrease;

39 - 13

=26

Then we can find the percentage decrease

26/13 ×100 =66.666..which can be written as 67.

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3 years ago
How do you simplify this problem
Aleonysh [2.5K]
The answer is 1/r to the power of 9
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4 years ago
Tyler paid $16 for 4 raffle tickets.<br> What is the price per ticket?
Mekhanik [1.2K]

Answer:

$4

Step-by-step explanation:

16 divide by 4 equals 4

5 0
3 years ago
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An optical inspection system is used to distinguish among different part types. The probability of a correct classification of a
dsp73

Answer:

P(X=0)=0.000008

P(X=1)=0.00176

P(X=2)=0.057624

P(X=3)=0.941192

Step-by-step explanation:

Probability of correct classification = p = 0.98

Probability of incorrect classification = q = 1 - p = 0.02

The probability of success and failure is the same for all the trials. The trials are independent of each other and the number of trials is fixed i.e. n = 3.

This satisfies all the conditions of a Binomial Experiment. So we can use Binomial experiment to model the probability mass function.

The general formula of a binomial probability is:

P(X=x)=^{n}C_{x}(p)^{x}q^{n-x}

Here x denote the number of successes, which can be {0, 1, 2, 3}. So we need to evaluate the above equation for each value of x to determine the probability Mass function of X, as shown below:

P(X=0)=^{3}C_{0}(0.98)^{0}(0.02)^{3-0}=0.000008\\\\ P(X=1)=^{3}C_{1}(0.98)^{1}(0.02)^{3-1}=0.001176\\\\ P(X=2)=^{3}C_{2}(0.98)^{2}(0.02)^{3-2}=0.057624\\\\ P(X=3)=^{3}C_{3}(0.98)^{3}(0.02)^{3-3}=0.941192

7 0
3 years ago
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