B is the answer cause when u put them all in that what i got
Answer:
Step-by-step explanation:
If the price is supposed to be dropping with each year, maybe your year/price chart would reflect that. Seems to me that the price rose between 2015 and 2016 and even by 2017 the value was still higher than it was in 2015.
I have no way of knowing how to fix this.
Let's ASSUME that the 2015 price was $71,445 and that the 2016 and 2017 prices are valid.
the decrease between 2015 and 2016 is (71445 - 68640) / 71445 = 0.03926
or 3.926%
the decrease between 2016 and 2017 is (68640 - 65945)/68640 = 0.03926
or 3.926%
so the price each year after new is
p = 71445(1 - 0.03926)ⁿ
or
71445(0.96074)ⁿ
where n is the number of years.
To get the monthly version, we divide the decrease by 12
p = 71445(1 - 0.03926/12)ˣ
or
p = 71445(1 - 0.00327)ˣ
or
p = 71445(0.99673)ˣ
where x is the number of months since new.
This may not be your exact answer, but the same method can be used if you get real numbers.
Answer:
Volume of the Tetrahedron T =
Step-by-step explanation:
As given, The tetrahedron T is bounded by the planes x + 2y + z = 2, x = 2y, x = 0, and z = 0
We have,
z = 0 and x + 2y + z = 2
⇒ z = 2 - x - 2y
∴ The limits of z are :
0 ≤ z ≤ 2 - x - 2y
Now, in the xy- plane , the equations becomes
x + 2y = 2 , x = 2y , x = 0 ( As in xy- plane , z = 0)
Firstly , we find the intersection between the lines x = 2y and x + 2y = 2
∴ we get
2y + 2y = 2
⇒4y = 2
⇒y =
= 0.5
⇒x = 2(
) = 1
So, the intersection point is ( 1, 0.5)
As we have x = 0 and x = 1
∴ The limits of x are :
0 ≤ x ≤ 1
Also,
x = 2y
⇒y = 
and x + 2y = 2
⇒2y = 2 - x
⇒y = 1 - 
∴ The limits of y are :
≤ y ≤ 1 - 
So, we get
Volume = 
= ![\int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}{[z]}\limits^{2-x-2y}_0 {} \, \, dy \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E1_0%20%7B%5Cint%5Climits%5E%7B1-%5Cfrac%7Bx%7D%7B2%7D%7D_%7By%20%3D%20%5Cfrac%7Bx%7D%7B2%7D%7D%7B%5Bz%5D%7D%5Climits%5E%7B2-x-2y%7D_0%20%7B%7D%20%5C%2C%20%20%20%5C%2C%20dy%20%20%5C%2C%20dx)
= 
= ![\int\limits^1_0 {[2y-xy-y^{2} ]}\limits^{1-\frac{x}{2}} _{\frac{x}{2} } {} \, \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E1_0%20%7B%5B2y-xy-y%5E%7B2%7D%20%5D%7D%5Climits%5E%7B1-%5Cfrac%7Bx%7D%7B2%7D%7D%20_%7B%5Cfrac%7Bx%7D%7B2%7D%20%7D%20%7B%7D%20%5C%2C%20%5C%2C%20dx)
= ![\int\limits^1_0 {[2(1-\frac{x}{2} - \frac{x}{2}) -x(1-\frac{x}{2} - \frac{x}{2}) -(1-\frac{x}{2}) ^{2} + (\frac{x}{2} )^{2} ] {} \, \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E1_0%20%7B%5B2%281-%5Cfrac%7Bx%7D%7B2%7D%20-%20%5Cfrac%7Bx%7D%7B2%7D%29%20%20-x%281-%5Cfrac%7Bx%7D%7B2%7D%20-%20%5Cfrac%7Bx%7D%7B2%7D%29%20-%281-%5Cfrac%7Bx%7D%7B2%7D%29%20%5E%7B2%7D%20%20%2B%20%28%5Cfrac%7Bx%7D%7B2%7D%20%29%5E%7B2%7D%20%5D%20%7B%7D%20%5C%2C%20%5C%2C%20dx)
= 
= 
= 1 - 1² +
- 0 + 0 - 0
= 1 - 1 +
= 
So, we get
Volume =
Answer:
the possible outcomes are :
- one (1)
- two (2)
- three (3)
- four (4)
- five (5)
- six (6)
2x+6=2(x+3)
Step-by-step explanation:
let x represent the unknown number