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Alexandra [31]
2 years ago
11

The figure below hows three quadrilaterals on a coordinate grid:

Mathematics
1 answer:
Aloiza [94]2 years ago
8 0
A and C are similar but not congruent
You might be interested in
PLEASE LOOK AT THE IMAGE. I’m despite. It’s probably easy.
Sloan [31]

Answer:

Correct answer:  (x - 10)² + y² = 441 / 4

Step-by-step explanation:

Given:

(a, b) = (10, 0)  the coordinates of the center of the circle

(10, 21/2)  circle passing through this point

The standard form of the circle equation is:

(x - a)² + (y - b)² = r²  where r is radius of the circle

We will replace the given coordinates of the center of the circle and the point it passes through to get the radius of the circle:

(10 - 10)² + (21/2)² = r²  ⇒ r² = (21/2)² = 441 / 4

r² = 441 / 4

(x - 10)² + y² = 441 / 4

God is with you!!!

6 0
3 years ago
If 14 g of a radioactive substance are present initially and 3 yr later only 7 g​ remain, how much of the substance will be pres
marishachu [46]
It would be 48 bc if you add it all up and subtract it and add again and multiply and divide and multiply within a and the substance of present after 6 yr you will see that i have wasted your time and that is not the answer
5 0
2 years ago
Edith is x years old. Her sister,Madison is six years older than her. Their mother is twice as old as Madison. Their aunt, Eliza
DENIUS [597]

Answer:

Step-by-step explanation:

Edith is x years old.

Her sister,Madison is six years older than her. This means that the age of Madison is x + 6

Their mother is twice as old as Madison. This means that the age of their mother is expressed as

2(x + 6)

= 2x + 12

Their aunt, Elizabeth is x years older than their mother. This means that the expression that represents Elizabeth's age in years is

2x + 12 + x

= 3x + 12

5 0
3 years ago
What is the 33rd term of this arithmetic sequence?<br><br> 12, 7, 2, -3, -8, …
sergiy2304 [10]
The answer be negative 158 or -158
7 0
2 years ago
The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes
saul85 [17]

Answer:

a)0.08  , b)0.4  , C) i)0.84  , ii)0.56

Step-by-step explanation:

Given data

P(A) =  professor arrives on time

P(A) = 0.8

P(B) =  Student aarive on time

P(B) = 0.6

According to the question A & B are Independent  

P(A∩B) = P(A) . P(B)

Therefore  

{A}' & {B}' is also independent

{A}' = 1-0.8 = 0.2

{B}' = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B')  (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

P(\frac{B'}{A}) = \frac{P(B'\cap A)}{P(A)} = \frac{0.4\times 0.8}{0.8} = 0.4

Part c)

Assume the events are not independent

Given Data

P(\frac{{A}'}{{B}'}) = 0.4

=\frac{P({A}'\cap {B}')}{P({B}')} = 0.4

P({A}'\cap {B}') = 0.4 x P({B}')

= 0.4 x 0.4 = 0.16

P({A}'\cap {B}') = 0.16

i)

The probability that at least one of them is on time

P(A\cup B) = 1- P({A}'\cap {B}')  

=  1 - 0.16 = 0.84

ii)The probability that they are both on time

P(A\cap  B) = 1 - P({A}'\cup {B}') = 1 - [P({A}')+P({B}') - P({A}'\cap {B}')]

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0
3 years ago
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