<em>Greetings from Brasil</em>
From radiciation properties:
![\large{A^{\frac{P}{Q}}=\sqrt[Q]{A^P}}](https://tex.z-dn.net/?f=%5Clarge%7BA%5E%7B%5Cfrac%7BP%7D%7BQ%7D%7D%3D%5Csqrt%5BQ%5D%7BA%5EP%7D%7D)
bringing to our problem
![\large{6^{\frac{1}{3}}=\sqrt[3]{6^1}}](https://tex.z-dn.net/?f=%5Clarge%7B6%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B6%5E1%7D%7D)
<h2>∛6</h2>
Answer:
40 square inch
Step-by-step explanation:
1/2+1/2= 1
1+1=2
2times 4= 8
8times 5= 40
if the problem has inches in it,
the answer will always equal to a square-inch
Answer:
.
Step-by-step explanation:
Using first order linear differential equation:


finding integrating factor:
I.F = 
I.F =
now,



hence the solution is
