<span> You need to use this formula to solve this exercise: P(t)=Ae^(k.t)
P(t) is the p</span><span>opulation of bacteria
A is the number of bacteria at the beginning of the experiment: 71
K is the growth rate
20 min= 1/3 hours
P(0)=71
P(1/3)= 71 ⇔ P= 71 x 2 ⇔142
142= 71 x e^k/3
2= </span><span>e^k/3
ln 2 = k/3
3ln 2=k
ln(2³)=k
</span>k=ln8
Answer:
using large amounts of natural resources
Explanation:
Carrying capacity of the environment can be defined as the optimal (maximum acceptable) level of use that an area can receive with a high level of satisfaction for users (visitors, researchers, employees) and minimal negative effects on resources. To some extent, the carrying capacity of the environment can be increased through agriculture, animal taming and the use of language. However, as a requirement to increase the carrying capacity of the environment is to engage in activity that does not adversely affect the area's resources, it is not possible to increase the carrying capacity of the environment by using large amounts of natural resources.
Answer:
See below
Explanation:
The correct statements can be two. Either:
1) The cell wall of plants is made up of cellulose
2) The cell wall of fungi is made up of chitin.
4 heterozygous offspring.the offspring will have red eyes but with the recessive white eye trait.
ATMOSPHERE LAYERS: Troposphere, Stratosphere, Mesosphere and Thermosphere
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