The general form of the quadratic equation is :
The discriminant is :
And the general solution is :
![x=\frac{-b\pm\sqrt[]{D}}{2\cdot a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7BD%7D%7D%7B2%5Ccdot%20a%7D)
So, there are 3 situations for D
1. D = 0
So, the roots of a quadratic equation are two similar roots
2. D > 0
so, roots of a quadratic equation are two different roots
3. D < 0
so, roots of a quadratic equation are not real, two comlex roots
Answer:
98.99%
Step-by-step explanation:
The combined reliability of both components must be 98%. Given that both components must be functional and have the same reliability 'r', the minimum value of 'r' that meets the system requirements is given by:
The level of reliability required for each component is 98.99%.
<span><span>In most statistical models
to represent easy percentages, circle is mostly preferred. It is purposefully
designed or rather allotted for functions that included 100%. A pie chart in
technical terms. Imagine an uneaten cake would
represent a 100%. </span></span>In most case scenarios,
when you eat one slice of the cake. You take a portion that decreases it 100%
or a whole presentation, for instance you took 25% slice of cake, what’s left
will be 75% and then when you put back again, the 25% slice will present the
whole 100%. In words, 25% slice of a cake you take, what’s left will just a
portion 75% and unless you put it back it will be whole again.
Before we do any solving, we need to simplify both sides.
On the left, we can simplify -2x + 3x - 5 to x - 5.
On the right, we can simplify 6 - 21 to -16.
So we have x - 5 = -16.
Solving from here, we add 5 to both sides to get x = -11.
<em>Answer:</em>
<em>a is greater than 1, so a−1 is positive.</em>
<em />
<em>The distance between a and 1 appears to be less than the distance between 1 and 0, so it looks like a is less than 2. Thus a−2 is negative.</em>
<em />
<em>b is negative, so −b is positive.</em>
<em />
<em>The distance between a and 0 appears to be less than the distance between b and 0, so it looks like |a| is less than |b|. Since b is negative and a is positive, a+b is negative.</em>
<em />
<em>a−b = a+−b. Since b is negative, −b is positive. a is also positive. Thus, a−b is positive.</em>
<em />
<em>Since |a| and |b| are both greater than 1, |ab| is also greater than 1 (this builds on the intuition students gained in fifth grade as in 5.NF.5). ab is negative since a is positive and b is negative. Thus, ab+1 is negative.</em>
