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andriy [413]
3 years ago
10

Let A be the area of circle of radius r that is changing with respect to time. If dr/dt is constant, is dA/dt constant? Expain.

Mathematics
1 answer:
UkoKoshka [18]3 years ago
8 0
Hello,

A=πr²
dA/dt=2πr*dr/dt
if dr/dt is constant, dA/dt is linear.
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Please help me with this
horrorfan [7]

Answer:

\dfrac{4000\pi}{3} ft³

Step-by-step explanation:

First, let's figure out how to get the <em>volume </em>of a sphere from its <em>surface area</em>. If r is the radius of our sphere, then

The formula for a sphere's surface area is A = 4\pi r^2

The formula for a sphere's volume is V=\frac{4}{3}\pi r^3

So to get from area to volume, we have to <em>divide the area by 3 </em>and then <em>multiply it by r.</em> Mathematically:

V=\frac{A}{3}r

Before we solve for V though, we need to find the radius of our sphere. Thankfully, we're given the surface area - 400\pi ft² - so we can use the area formula to find that radius:

A=4\pi r^2=400\pi\\r^2=100\\r=10

And now that we have our radius, we can put it into our volume formula to find

V=\frac{A}{3} r=\frac{400\pi}{3}(10)=\frac{4000\pi}{3} ft³

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