your answer would be C I just took this lesson last semester
Explanation:
As it is known that molarity is the number of moles present in a liter of solution.
Mathematically, Molarity =
As it is given that molarity is 0.10 M and volume is 10.0 ml. As 1 ml equals 0.001 L. Therefore, 10.0 ml will also be equal to 0.01 L.
Hence, putting these values into the above formula as follows.
Molarity =
0.10 M =
no. of moles = 0.001 mol
As molar mass of KCN is equal to 65.12 g/mol. Therefore, calculate the mass of KCN as follows.
No. of moles =
0.001 mol =
mass = 0.06152 g
Thus, we can conclude that 0.06152 grams of KCN are in 10.0 ml of a 0.10 M solution.
Answer:
The atomic weight of the substance is 2.4837 X 10⁻³ amu
Explanation:
For a body-centered cubic structure, the edge length is given as
Given edge length in this problem is 287 pm
Volume of a sphere = = 1.333π*(124.27 X 10⁻¹²)³ = 5.206 X 10⁻³⁴ m³ X 10⁶ cm³ = 5.206 X 10⁻²⁸ cm³
Mass = density X volume
Mass = (7.92 g/cm³) *(5.206 X 10⁻²⁸ cm³) = 41.23 10⁻²⁸ g
1.66 x 10⁻²⁴g = 1 amu
41.23 10⁻²⁸ g = 2.4837 X 10⁻³ amu
Therefore, the atomic weight of the substance is 2.4837 X 10⁻³ amu