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3 years ago

Y'all help me please!!!

Chemistry

1 answer:

marysya [2.9K]3 years ago

7 0

The answer is b, the moon is smaller and has less gravity. hope this helps

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Gravity is the force that keeps the planets in orbit.

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3 years ago

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How do trends in the periodic table help predict the properties of an element

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As you move around there is a change in: electronegativies, ionisation energies, atomic radius etc. different amounts of these properties are going to effect how the element acts

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2 years ago

if it takes 54 ml of 0.100 M naoh to neutralize 125ml of an hcl solution, what is the concentration of the hcl

vichka [17]

Answer:

c = 0.0432moldm ^−3

Explanation:

The first step would be to find the molar ratio in the reaction. Now generally, one can simplify strong acid-strong base reaction by saying:

Acid+Base ->Salt+ Water

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2 years ago

Write the net ionic equation for the precipitation reaction that occurs when aqueous solutions of chromium(III) bromide and pota

expeople1 [14]

Explanation:

An ionic equation will be the one in which all the participating species will be present as ions.

The given reaction will be as follows.

$CrBr_{3} + K_{2}CO_{3} \rightarrow Cr_{2}(CO_{3})_{3}(s) + KBr$

Balancing this equation by multiplying $CrBr_{3}$ by 2 and $K_{2}CO_{3}$ by 3 on reactant side. Whereas multiply KBr by 6 on product side.

$2CrBr_{3} + 3K_{2}CO_{3} \rightarrow Cr_{2}(CO_{3})_{3}(s) + 6KBr$

Hence, the net ionic equation will be as follows.

$2Cr^{3+}(aq) + 3CO^{2-}_{3}(aq) + 6K^{+} + 6Br^{-} \rightarrow Cr_{2}(CO_{3})_{3}(s) + 6K^{+} + 6Br^{-}$

As both $K^{+}$ and $Br^{-}$ are spectator ions. Hence, the net ionic equation will be as follows.

$2Cr^{3+}(aq) + 3CO^{2-}_{3}(aq) \rightarrow Cr_{2}(CO_{3})_{3}(s)$

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2 years ago

A) What mass in grams of H20 is needed to react completely with 40.0 g of

Step2247 [10]

Answer:

$m_{H_2O}=9.24gH_2O$

Explanation:

Hello there!

In this case, since there is a 2:2 mole ratio between sodium peroxide and water according to the given reaction, it is possible to apply the following stoichiometric setup for the calculation of the required mass of water:

$m_{H_2O}=40.0gNa_O_2*\frac{1molNa_O_2}{78gNa_O_2}*\frac{2molH_2O}{2molNa_O_2} *\frac{18.02gH_2O}{1molH_2O} \\\\m_{H_2O}=9.24gH_2O$

Best regards!

7 0

2 years ago