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3 years ago

How do I do this? also the first part that is answered is wrong

Mathematics

1 answer:

lord [1]3 years ago

4 0

Answer:

i would say for the second one 2.5 and the first one about 30

Step-by-step explanation:

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(1 ÷ x- 1)+(2÷ x+2)=(3÷2) solve and check for extraneous solutions

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$\frac{1}{x-1}+ \frac{2}{x+2}= \frac{3}{2}$
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$\frac{x+2+2(x-1)}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}$
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$\frac{3x+1}{(x-1)(x+2)}= \frac{3(x^2+x-2)}{2}$
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$\frac{3x+1}{(x^2+x-2)}= \frac{3x^2+3x-6)}{2}$
$\frac{2(3x+1)}{2(x^2+x-2)}= \frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}$
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$\frac{2(3x+1)-3x^2+3x-6}{2(x^2+x-2)}=0$

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